3 years ago

Find R, if 5R²+ (22.255)² = (27.45)²

Mathematics

1 answer:

denpristay [2]3 years ago

8 0

Answer:

R = 7.186340863

Step-by-step explanation:

5R^2 + 495.285025 = 753.5 5025

5R^2 = 258.217475

R^2 = 51.643495

R = 7.186340863

Are u Asian

You might be interested in

Is he cute or not his name is Arlo

AVprozaik [17]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

I had $20.00 my mom gave me $10.00 my dad gave me $30.00 my aunt and uncle gave me $100.00 I had another $1.00 how much did I ha

fenix001 [56]

Answer:

you had $161.00

Step-by-step explanation:

20+10=30

30+30=60

60+100+1=161

$161

5 0

3 years ago

2. JI. has coordinates J(-6, 1) and Z(-4, 3). Find the coordinates of the midpoint.

AleksandrR [38]

Answer:

(- 5, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

Here (x₁, y₁ ) = (- 6, 1) and (x₂, y₂ ) = (- 4, 3) thus

midpoint = $\frac{-6-4}{2}$ , $\frac{1+3}{2}$ ) = ( $\frac{-10}{2}$ , $\frac{4}{2}$ ) = (- 5, 2 )

7 0

3 years ago

Write the polynomial in standard form and identify the zeros of the function and the x-intercepts of its graph.

iragen [17]

$f(x)=(x-3i)(x+3i)
\\f(x)=x^2-(3i)^2
\\f(x)=x^2-9i^2
\\f(x)=x^2-9(-1)
\\f(x)=x^2+9$

<span>x-intercepts of its graph

</span> $f(x)=0
\\(x-3i)(x+3i)=0
\\x-3i=0 \Rightarrow x=3i
\\x+3i=0 \Rightarrow x=-3i$ <span>
</span>

3 0

3 years ago

Solve – x2 + 5x – 2 = x2 - x by graphing. Round your answers to the nearest hundredth, if necessary.

Paraphin [41]

Answer:

${}^{6} \sqrt{3a} = {}^{6} \sqrt{3a} \\ {}^{3} \sqrt{5a} = {}^{6} \sqrt{5 {}^{2} } a {}^{2} = {}^{6} \sqrt{25} \\ \sqrt{za} = {}^{6} \sqrt{2 {}^{3} } a {}^{3} = {}^{6} \sqrt{8a {}^{3} }$

8 0

3 years ago

Find R, if 5R²+ (22.255)² = (27.45)²​

Find R, if 5R²+ (22.255)² = (27.45)²