Answer:
1 side would be 4.0, then the next 4.0, the very botton is a 90 degree
Step-by-step explanation:
Answer:
251
Step-by-step explanation:
Tn=5n+1
e.g.T1=5(1)+1
=6
e.g.T2=5(2)+1
=11
e.g.T3=5(3)+1
=16
e.g.T4=5(4)+1
=21
Answer:T50=5(50)+1
=251
Answer:
259
Step-by-step explanation:
491+624=1115. 1374-1115=259
Answer:
53.33
Step-by-step explanation:
finding area of ΔPAM
using similar triangles

16 = 12x; x = 
ΔPAM = 4/3 * 4 * 1/2 = 16/6 = 8/3
ΔPAL = 4 * 12 * 1/2 = 24
24 + 8/3 = 80/3 (using fraction form for now, will round later)
since there are two ΔPLM (ΔLMU has same area since they are congruent)
we can multiply 80/3 by 2
80/3 * 2 = 160/3 = 53.33
In polar coordinates, the region
is the set of points

and we have
and
. So the integral, converted to polar, is

Substitute
to get
