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3 years ago

Which of the following graphs shows a negative linear relationship with a correlation coefficient

Mathematics

1 answer:

Aloiza [94]3 years ago

8 0

Answer : Graph D

Question says negative linear relationship. It means the slope is negative.

Option A and C have positive slope because the dots on graph goes up.

So we ignore A and C graph

B and D graphs have negative slope.

Given Correlation coefficient r is close to -0.5

In Graph B the dots are close to one another . It means the correlation coefficient r is close to - 1

Graph D shows a negative linear relationship with a correlation coefficient r close to =-0.5

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Paul's Pizzeria sells 45 cheese pizzas and 20 pepperoni pizzas each week.

Zina [86]

Ratio is demonstrated by " : " sign.
Ratio of cheese: pepperoni
45:20
Simplify and divide each side by 5
9:4

A. 9:4

Hope this helps :)

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2 years ago

If the area of the blue square is 144 units2 and the area of the pink square is 1225 units2, then the length of the hypotenuse i

navik [9.2K]

Answer: 37 units

Step-by-step explanation:

$Blue=144units^2$ This also works as the height of the triangle.

$Pink=1225units^2$ This also works as the base of the triangle.

Let's call pink ''a'', and blue ''b''. The side we're looking for ''c'' is the hypothenuse.

To find the values of a and b, use the area formula of a square and solve for a side. In this case, since we're going to need the squared values, this step can be omitted.

$Formula: A=s^2$

$s=\sqrt[]{A}$

Let's work with Blue.

$s=\sqrt[]{144units^2} \\s=12units$

Now Pink.

$s=\sqrt[]{1225units^2}\\s=35units$

So we have a triangle with a base of 35 units and a height of 12 units.

Now let's use the pythagoream's theorem to solve.

$c^2=a^2+b^2\\c=\sqrt[]{a^2+b^2} \\c=\sqrt[]{(12units)^2+(35units)^2}\\c=\sqrt[]{144units^2+1225units^2}\\ c=\sqrt[]{1369units^2}\\ c=37units$

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3 years ago

When lava is expelled from a volcano, it temperature may vary from 700 degrees Celsius to 1200 degrees Celsius. Write an absolut

ValentinkaMS [17]

Answer:

Ix - 950°C I ≤ 250°C

Step-by-step explanation:

We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.

And that this temperature is x.

This means that the minimum value of x is 700°C while maximum of x is 1200 °C

Let's find the average of the two temperature limits given:

x_avg = (700 + 1200)/2 =

x_avg = 1900/2

x_avg = 950 °C

Now let's find the distance between the average and either maximum or minimum.

d_avg = (1200 - 700)/2

d_avg = 500/2

d_avg = 250°C.

Now absolute value equation will be in the form of;

Ix - x_avgI ≤ d_avg

Thus;

Ix - 950°C I ≤ 250°C

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