Question

Question 8 of 10

Answer 1

Answer:

B

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ = $a^{\frac{1}{2} }$

Thus

($\sqrt{a}$ )² = $a^{\frac{1}{2} }$ × $a^{\frac{1}{2} }$ = $a^{(\frac{1}{2}+\frac{1}{2}) }$ = $a^{1}$ = a → B