we are given

To find solution , we can factor it and then we can solve for x
step-1: Factoring


step-2: Solve for x




so, option-C and option-F...........Answer
Answer:
2) x = -2
, y = 2
3) no solution exists
Step-by-step explanation:
Solve the following system:
{-2 x - 3 y = -2
y = 2 x + 6
Hint: | Perform a substitution.
Substitute y = 2 x + 6 into the first equation:
{-2 x - 3 (2 x + 6) = -2
y = 2 x + 6
Hint: | Expand the left hand side of the equation -2 x - 3 (2 x + 6) = -2.
-2 x - 3 (2 x + 6) = (-6 x - 18) - 2 x = -8 x - 18:
{-8 x - 18 = -2
y = 2 x + 6
Hint: | Choose an equation and a variable to solve for.
In the first equation, look to solve for x:
{-8 x - 18 = -2
y = 2 x + 6
Hint: | Isolate terms with x to the left hand side.
Add 18 to both sides:
{-8 x = 16
y = 2 x + 6
Hint: | Solve for x.
Divide both sides by -8:
{x = -2
y = 2 x + 6
Hint: | Perform a back substitution.
Substitute x = -2 into the second equation:
Answer: {x = -2
, y = 2
Answer:
A. (6,0)
Step-by-step explanation:
4a- 5b = 24
Check each point to see if its is true
A. (6,0)
4(6) - 5(0) = 24
24 = 24
true
B. (-5, -2)
4(-5) -5(-2)= 24
-20 +10 = 24
-10 =24
False
C. (0,6)
4(0) -5(6) =24
-30 =24
False
D. (-2, -5)
4(-2) -5(-5)=24
-8+25=24
18=24
False
Answer:
W=5
Step-by-step explanation:
W=Width=Length + 1
L = Length
Area = Length * Width = 20
Area = L * W = L * (L+1) = 20
Distribute the L: L^2 + L = 20
Subtract 20 from both sides: L^2 + L -20 = 20-20
Simplify: L^2+L-20=0
Factor (L-4)(L+5)=0
Solve using the zero property: L-4=0, L=4 L+5=0, L=-5
The two options for length are 4 and -5. Only 4 will work for L since it cannot be negative. Width is Length + 1 = 5