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Murljashka [212]
3 years ago
14

Which equation represents the circle shown in the graph?

Mathematics
1 answer:
marta [7]3 years ago
8 0

Answer:

i think 3

Step-by-step explanation:

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Make d the subject of the formula h = d/3 + 2​
Thepotemich [5.8K]
First what you would have to do is distribute the reciprocal to the (d/3 + 2) and the d/3 is canceled out. You are left with h=6/d. When you put the h over 1 in a fraction, it stays the same. Like in trig, you switch the d and the h and you have d/1=6/h.

d=6/h
4 0
3 years ago
Please help brainliest and 20 points!
Nadya [2.5K]

Answer:

I'm so sorry I can't help haven't learned how to do that yet

4 0
3 years ago
3. Classify the number: -4
BabaBlast [244]

Answer:

Aight.

Rational, Real, Integer, Negative

7 0
3 years ago
Read 2 more answers
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
3 years ago
Alex, Bob, and Claudia split 126 cm wire evenly among themselves. They then proceeded to cut their pieces of wire into smaller,
Westkost [7]
<h3>Answer:</h3>
  • Bob
  • 18 cm
<h3>Step-by-step explanation:</h3>

If Alex cut his wire 18 times, he ended up with 19 equal pieces. He kept 7, so has 7/19 of his 1/3 of the wire.

Bob cut his wire 20 times, so ended up with 21 pieces, of which he kept 9. So he has 9/21 = 3/7 of his 1/3 of the wire.

Claudia kept 1/13 of her 1/3 of the wire, so has the smallest piece.

Bob kept (3/7)·(1/3)·126 cm = 18 cm.

Alex kept (7/19)·(1/3)·126 cm ≈ 15.47 cm.

Bob kept the longest part of the original wire.

3 0
3 years ago
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