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frosja888 [35]
4 years ago
6

Please answer this !!!!!

Mathematics
1 answer:
crimeas [40]4 years ago
3 0

2(-2 - 4p) + 2(-2p - 1)

= -4 -8p + -4p - 2

= -12p - 6

Answer: A


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L33. Solve 41x - 7 + 12 = 28<br> Solution(s).
s2008m [1.1K]

Answer:

41x-7+12=28

41x+5=28

41x=28-5

41x= 23

x= 23/41

x= 0.56

7 0
3 years ago
Last year Kaitlin opened an investment account with $7600. At the end of the year, the amount in the account had increased by 6.
Doss [256]

The increase was: 494

7 0
3 years ago
Josh will take 10 tests in 5 weeks of school. How many tests will he have taken after 7 weeks?
stira [4]
<h2>10/5=2 test per week</h2><h2>7x2=14</h2><h2>Josh took 14 test in 7 weeks</h2>
5 0
4 years ago
Write the quadratic equation in factored form. Be sure to write the entire equation. x2 - 5x - 24 = 0
Vitek1552 [10]

​x² - 5x - 24 = 0

First, we have to solve the quadratic equation and find the two values of x that fit the equation.​

x =  \frac{5+- \sqrt{5^{2} + 4*1*24 } }{2*1}  =  \frac{5+- \sqrt{25 + 96} }{2} =  \frac{5+- \sqrt{121} }{2}  =  \frac{5+-11}{2}​

There are two values of x that fit:​

x₁ = (5+11)/2 = 16/2 = 8​

x₂ = (5-11)/2 = -6/2 = -3​

Now I can restate the original equation in terms of a product of factors, with this product being equal to zero:​

(x - x₁) * (x - x₂) = 0​

ANSWER ​(x-8) * (x+3) = 0

Now I can solve each factor by setting each one equal to zero and solving the resulting linear equations:​

x - 8 = 0 or x + 3 = 0​

x = 8 or x = -3​

We can check that these two values are the solution to the original quadratic equation.​

x² - 5x - 24 = 0​

​First value

​8² -5*8 -24 = 0

64 - 40 -24 = 0​

0 = 0 ¡Checked!​

Second value​

(-3)² -5(-3) -24 = 0​

9 + 15 -24 = 0​

0 = 0 ¡Checked!​

​Hope this helps!

​\textit{\textbf{Spymore}}​​​

8 0
4 years ago
Help me answer as soon as possible, thank you!A and B only
MArishka [77]

Answer:

(a)4

(b)7

Explanation:

Given f(x) and g(x) defined below:

\begin{gathered} f(x)=\{(3,2),(5,1),(7,4),(9,3),(11,5)\} \\ g(x)=\{(1,3),(2,5),(3,7),(4,9),(5,11)\} \end{gathered}

(a) f(g(3))

\begin{gathered} g(3)=7 \\ f\lbrack g(3)\rbrack=f(7)=4 \\ \implies f\lbrack g(3)\rbrack=4 \end{gathered}

The value of f(g(3)) is 4.

(b) (g o f)(9)

\begin{gathered} (g\circ f)(9)=g\lbrack f(9)\rbrack \\ f(9)=3 \\ g\lbrack f(9)\rbrack=g(3)=7 \\ \implies(g\circ f)(9)=7 \end{gathered}

The value of (g o f)(9) is 7.

3 0
1 year ago
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