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denis-greek [22]
3 years ago
9

Help me with this please!!

Mathematics
1 answer:
Alika [10]3 years ago
5 0
19 hundreds. 19 time 100 is 1900
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Help me please I need the help
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Answer:

p - 3

Step-by-step explanation:

Key expression: 3 fewer than

Fewer than = subtract from

subtract 3 from a number, p

This means that the expression would be p - 3

Because you are subtracting 3 from a number ( p )

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My dad disconnected my wifi off my pc with our wifis own app does anyone know how to reconnect my pc to the wifi?
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fijate tu modem a ver si se soluciona si no al tecnico

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2 years ago
10 points and brainliest
Rasek [7]

Answer:

y = (1/4)x+3

Step-by-step explanation:

7 0
3 years ago
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Which represents all the values of x that make the rational expression 2x-4 over x-5 undefined?
julsineya [31]
X=5 because the denominator can never equal zero or it will be undefined. and 5-5=0
7 0
3 years ago
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Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar
Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

((a, b), (c, d))\in R

Where R is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

\forall a \in A \Rightarrow (a,a) \in R

Here we need to prove:

\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R

As per the given relation:

((a,b), (a,b) ) \Rightarrow ab =ab which is true.

\therefore R is reflexive.

2. Now, let us check symmetric property:

Symmetric property means:

\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R

Here we need to prove:

\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R

As per the given relation:

((a,b),(c,d)) \in R means ad = bc

((c,d),(a,b)) \in R means cb = da\ or\ ad =bc

Hence true.

\therefore R is symmetric.

3. R to be transitive, we need to prove:

if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R

((a,b),(c,d)) \in R means ad = cb.... (1)

((c,d), (e,f)) \in R means fc = ed ...... (2)

To prove:

To be ((a,b), (e,f)) \in R we need to prove: fa = be

Multiply (1) with (2):

adcf = bcde\\\Rightarrow fa = be

So, R is transitive as well.

Hence proved that R is an equivalence relation.

8 0
3 years ago
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