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3 years ago

Help me with this please!!

Mathematics

1 answer:

Alika [10]3 years ago

5 0

19 hundreds. 19 time 100 is 1900

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Help me please I need the help

serious [3.7K]

Answer:

p - 3

Step-by-step explanation:

Key expression: 3 fewer than

Fewer than = subtract from

subtract 3 from a number, p

This means that the expression would be p - 3

Because you are subtracting 3 from a number ( p )

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2 years ago

My dad disconnected my wifi off my pc with our wifis own app does anyone know how to reconnect my pc to the wifi?

Inga [223]

fijate tu modem a ver si se soluciona si no al tecnico

4 0

2 years ago

10 points and brainliest

Rasek [7]

Answer:

y = (1/4)x+3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which represents all the values of x that make the rational expression 2x-4 over x-5 undefined?

julsineya [31]

X=5 because the denominator can never equal zero or it will be undefined. and 5-5=0

7 0

3 years ago

Read 2 more answers

Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar

Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

$((a, b), (c, d))\in R$

Where $R$ is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

$\forall a \in A \Rightarrow (a,a) \in R$

Here we need to prove:

$\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R$

As per the given relation:

$((a,b), (a,b) ) \Rightarrow ab =ab$ which is true.

$\therefore$ R is reflexive.

2. Now, let us check symmetric property:

Symmetric property means:

$\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R$

Here we need to prove:

$\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R$

As per the given relation:

$((a,b),(c,d)) \in R$ means $ad = bc$

$((c,d),(a,b)) \in R$ means $cb = da\ or\ ad =bc$

Hence true.

$\therefore$ R is symmetric.

3. R to be transitive, we need to prove:

$if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R$

$((a,b),(c,d)) \in R$ means $ad = cb$ .... (1)

$((c,d), (e,f)) \in R$ means $fc = ed$ ...... (2)

To prove:

To be $((a,b), (e,f)) \in R$ we need to prove: $fa = be$

Multiply (1) with (2):

$adcf = bcde\\\Rightarrow fa = be$

So, R is transitive as well.

Hence proved that R is an equivalence relation.

8 0

3 years ago