Hello!
First of all, 6 and 10 are not prime numbers as they both have at least two pairs of factors (one factor pair plus one and itself).
Anything multiplied by two is even. Therefore, a) 2 counterexamples the statement. Just to show why 7 doesn't work, seven multiplied by 3 is 21, which is odd, and 7 times 7 is 49, and 7 times 5 is 35 (all prime multipliers). The only one that works is two.
I hope this helps!
Answer:
Step-by-step explanation:
Answer:

Step-by-step explanation:
Basically, if you want to find the probability of getting either outcomes, you will need to subtract the probability of getting neither outcomes in the question. The probability for both outcomes are 7/9 and 5/9 respectively. You will have to multiply to get the probability of getting both of the non-desired outcomes. Hence, it gives the equation above
Answer:
a. x^2+2xy+y^2
Step-by-step explanation:
I hope this helps
Here’s the correct answer, how I got it, and something to help you for next time. I know it’s a lot of words but if u read the explanation it might help you :)