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alekssr [168]
3 years ago
5

The line is parallel to y= 2x + 1 and passes through point (-2,-1).

Mathematics
1 answer:
inessss [21]3 years ago
7 0

Answer:

y = 2x + 3

Step-by-step explanation:

To find the equation of a line, you need 2 things:

1) gradient/slope

2) 1 set of x and y coordinates

To find the slope:

If 2 lines are parallel, they have exactly the same gradient.

So, this line will have a slope of 2 as well (the slope of a line is the coefficient of x in the equation).

To find the equation of the line:

<u>Start with this generic equation:</u>

y - y1 = m (x-x1)

<u>We know that:</u>

(x1, y1) -> (-2, -1) and m= 2

<u>So, we can substitute for the equation:</u>

y- (-1) = 2 (x -(-2))

<u>Simplify, by expanding the brackets:</u>

y + 1= 2 (x+2)

y + 1 = 2x + 4

<u>Rearrange for y:</u>

y = 2x + 3

To double check:

1) The coefficient of x is the slope, we have 2x and the slop is 2, so that's correct

2) Sub in x= -2, and you should get y=-1

y = -4 + 3 = -1, so that's correct too

Hope that helped : )

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Kitty [74]

Answer:

Point T is the right angle of the triangle, so RTS = 90 degrees

8x + 18 = 90 (degrees)

8x = 72

x = 9 degrees

Step-by-step explanation:

8 0
3 years ago
Using the equation y=(1/2)x, when x=0 what is the value y ?
weeeeeb [17]

Answer:

.

Step-by-step explanation:

3 0
3 years ago
Need help ASAP <br> questions in the pics i have sent
Cloud [144]

Answer:

Step-by-step explanation:

Picture 1

In right triangle ABC,

Side AB is the opposite side of angle C.

Picture 2

In triangle MKL,

tan(∠M) = \frac{\text{Opposite side}}{\text{Adjacent side}}

             = \frac{KL}{KM}

             = \frac{15}{8}

Option (1) is the answer.

Picture 3

In ΔXYZ,

sin(∠Z) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

            = \frac{XY}{XZ}

For the length of XY we will apply Pythagoras theorem in ΔXYZ,

XZ² = XY² + YZ²

XY² = XZ² - YZ²

      = (40)² - (32)²

XY = √576

     = 24

sin(Z) = \frac{24}{40}

sin(Z) = \frac{3}{5}

Picture 4

In right triangle DEF,

Cos(D) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

           = \frac{EF}{DF}

           = \frac{75}{72}

           = \frac{25}{24}

Picture 5

In ΔABC,

tan(63°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

tan(63°) = \frac{BC}{AB}

AB = \frac{BC}{\text{tan}(63)}

AB = \frac{8}{\text{tan}(63)}

AB = 4.0762 ≈ 4 m

Option (3) will be the answer.

7 0
3 years ago
Anyone know which one is the right one
sergiy2304 [10]

1) the square root of 64=8

2) The square root of a^4=a^2

3) b^5=b√b

so the first amount simplifies to 8a²b²√b

4) ∛64=4, as 4×4×4=64

5) ∛a^5=a√a²

6)∛b^4=b√b

so...the second amount is equal to 4ab∛a²b

The last one should be correct

Hope this helped :)


6 0
3 years ago
2sin3x-<br><img src="https://tex.z-dn.net/?f=" id="TexFormula1" title="" alt="" align="absmiddle" class="latex-formula"><br>1 =
olasank [31]
2sin3x-1=0

sin3x=1/2

sinx=1/2, x=pi/6, 5pi/6

3x=arcsin(1/2)
x=1/3*pi/6
[x=pi/18]
8 0
3 years ago
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