∠n = ∠p
p - 3x = 10
5x - n = 8......> 5x - p = 8
by adding the two equations
2x = 18 , x = 9
p = 37
m∠M = 180 - (2*37) = 106°
Using the z-distribution, it is found that the 95% confidence interval for the difference is (-1.3, -0.7).
<h3>What are the mean and the standard error for each sample?</h3>
Considering the data given:


<h3>What is the mean and the standard error for the distribution of differences?</h3>
The mean is the subtraction of the means, hence:

The standard error is the square root of the sum of the variances of each sample, hence:

<h3>What is the confidence interval?</h3>
It is given by:

We have a 95% confidence interval, hence the critical value is of z = 1.96.
Then, the bounds of the interval are given as follows:
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer: R(x) = 0.25x + 500
Flat fee is computed by:
The sales price of each tile is 0.25 and the customer only bought 10,000 tiles.
So, $0.25 x 10,000 = $2500
So the total sales price per tile sold was $2,500.
The buyer paid $3,000, so the flat fee was included there.
So, $3,000 - $2,500 = $500
So the flat fee was $500.
~
The revenue function is the total income from producing the units. And it has a equation of: R(x) = price per unit x number of units sold plus any fee that is included
So the function describing the revenue of the tile from this sale is:
R(x) = 0.25x + 500
(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]
Answer:
Following are the solution to the given points:
Step-by-step explanation:
In point 1:
The Reflexive closure:
Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is 
Thus, the reflexive closure: 
In point 2:
The Symmetric closure:
R relation symmetrically closes by adding(b,a) to R for each (a,b) of R Therefore, here (b,a) is:

Thus, the Symmetrical closure:

Answer:
-x-2; x
2
Step-by-step explanation:
-->
-->
-(x+2); x CAN'T equal 2, because the denominator of the original fraction would be 0, which would make the term undefined.