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4 years ago

I'll give 30 points and brainlist

Mathematics

1 answer:

Kamila [148]4 years ago

7 0

Answer:

100 degrees

Step-by-step explanation:

Arc QM = Arc QN = 130°

Arc MN = 360 - Arc QM - Arc QN

= 360 - 2(130)

= 360 - 260

= 100°

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The prices per pound of different types of nuts are shown. write an expression that can be used to find the total cost of 2 poun

Soloha48 [4]

Answer:

expression for total cost is given by

$0.80(3.95x+4.25y+5.99z)$

Step-by-step explanation:

Here we need to find the expression for the total cost

Let us find the cost for x pounds of peanut , y pounds of cashews and z pounds of almonds

cost of 1 pound of peanut = $3.95

cost of x pounds of peanut = $3.95x

cost of 1 pound of cashews = $4.25

cost of y pounds of cashews = $4.25y

cost of 1 pounds of almonds = $5.99

cost of z pounds of almonds = $5.99z

total cost = $3.95x+4.25y+5.99z$

cost after 20% off = total cost - 20% of total cost

= 80% of total cost

cost after 20% off =80% $(3.95x+4.25y+5.99z)$

cost after 20% off = $0.80(3.95x+4.25y+5.99z)$

now we can plug x= 2 , y= 3 and z=1

so we have

cost after 20% off = $0.80(3.95(2)+4.25(3)+5.99(1))$ =$ 21.31

6 0

3 years ago

Which are not lengths of a right triangle?

zubka84 [21]

It’s D Have Ah Good Day

8 0

3 years ago

I need I will most definitely mark brain-iest ?!

3241004551 [841]

Answer:

The very first one is 22

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How can we show a num ( k ) increased by 8 ?

N76 [4]

Answer:

k + 8

Step-by-step explanation:

4 0

3 years ago

2. Suppose 27 blackberry plants started growing in a yard. Absent constraint, the blackberry plants will spread by 80% a month.

Marta_Voda [28]

Explanation

The question indicates we should use a logistic model to estimate the number of plants after 5 months.

This can be done using the formula below;

$\begin{gathered} P(t)=\frac{K}{1+Ae^{-kt}};A=\frac{K-P_{0_{}}}{P_0}_{} \\ \text{From the question} \\ P_0=\text{ Initial Plants=27} \\ K=\text{Carrying capacity =140} \end{gathered}$

Workings

Step 1: We would need to get the value of A using the carrying capacity and initial plants that started growing in the yard.

This gives;

$\begin{gathered} A=\frac{140-27}{27} \\ A=\frac{113}{27} \end{gathered}$

Step 2: Substitute the value of A into the formula.

$P(t)=\frac{140}{1+\frac{113}{27}e^{-kt}}$

Step 3: Find the value of the constant k

Kindly recall that we are told that the plants increase by 80% after each month. Therefore, after one month we would have;

$\begin{gathered} P(1)=27+(\frac{80}{100}\times27) \\ P(1)=\frac{243}{5} \end{gathered}$

We can then have that after t= 1month

$\begin{gathered} \frac{140}{1+\frac{113}{27}e^{-k\times1}}=\frac{243}{5} \\ Flip\text{ the equation} \\ \frac{1+\frac{113}{27}e^{-k}}{140}=\frac{5}{243} \\ 243(1+\frac{113}{27}e^{-k})=700 \\ 243+1017e^{-k}=700 \\ 1017e^{-k}=700-243 \\ 1017e^{-k}=457 \\ e^{-k}=\frac{457}{1017} \\ -k=\ln (\frac{457}{1017}) \end{gathered}$

Step 4: Substitute -k back into the initial formula.

$\begin{gathered} P(t)=\frac{140}{1+\frac{113}{27}e^{\ln (\frac{457}{1017})t}} \\ =\frac{140}{1+\frac{113}{27}(e^{\ln (\frac{457}{1017})})^t} \\ P(t)=\frac{140}{1+\frac{113}{27}(\frac{457}{1017}^{})^t} \\ \end{gathered}$

The above model is can be used to find the population at any time in the future.

Therefore after 5 months, we can estimate the model to be;

$\begin{gathered} P(5)=\frac{140}{1+\frac{113}{27}(\frac{457}{1017}^{})^5} \\ P(5)=\frac{140}{1.07668} \\ P(5)=130.029\approx130 \end{gathered}$

Answer: The estimated number of plants after 5 months is 130 plants.

8 0

1 year ago