A^2+b^2=C^2
=
4+144=148
The square root of 148 is 12.165
round it down to 12
Hope this helps
Answer:
2x + 9 with a remainder of 45.
Step-by-step explanation:
If the divisor is x-5, use the divisor 5 in synthetic div.
Taking the coefficients 2, -1 and 4 from the dividend, we get:
------------------
5 / 2 -1 4
10 45
--------------------
2 9 49
This tells us that the quotient is 2x + 9 and that the remainder is 49.
<span>3x^2−2x+7=0
</span>3x^2−2x+1/3+7−1/3=<span>0
</span><span>3<span>(x^2−2x/3+1/9)</span>+7−1/3=0
</span><span>3<span><span>(x−1/3)^</span>2</span>+(21−1)/3=0
</span><span>3<span><span>(<span>x−1/3</span>)^</span>2</span>=−<span>20/3
</span></span><span><span>(<span>x−<span>1/3</span></span>)^</span>2</span>=−<span>20/9</span>
The correct answer is C).
