Answer:
Ti lah 13435364646166161611646646767676797979494
In equation, let x be the number of male students
a be the number of adults
y be the number of female students.
x= 7a+1
a= x/7 -1
y= x/2 or (7a + 1)/ 2
a + b = 82, let b be the number of students.
a + (x + y) = 82
a + [7a+1 + (7a+1)/2] = 82
a + [{2(7a+1) + 7a+1} / 2] = 82
a + [(14a +2 + 7a +1) / 2] = 82
a + [(21a + 3) / 2] = 82
(2a+ 21a + 3) / 2 = 82
(23a + 3) / 2 = 82
23a + 3 = 164
23a = 164 -3
23a = 161
a = 7
x = 7(7) +1, 49+1 = 50 male students
y=x/2, 50/2, 25 female students
50(male students) + 25(female students) + 7 (adults) = 82
Answer:
655Step-by-step explanation:
5
The paper is 16 cm by 34 cm to start with, so we started with area
.. (16 cm)*(34 cm) = 544 cm^2
A circle of diameter 16 cm has been removed. The area of that circle is
.. π*(d/2)^2 = 3.14*(16 cm/2)^2 = 200.96 cm^2
Then the area of the paper that remains is
.. 544 cm^2 -200.96 cm^2
.. = 343.04 cm^2
Answer:
4 White, 3 Blue
Step-by-step explanation:
5w+2b=26
Closest five multiple that leaves an even remainder is 4.
5×4=20
26-20=6÷2=3