<span>(3y*5b)*10 = __(5b*10)
</span>15yb *10 = __(5b*10)
150yb = 3y(50b)= 150yb
Do you have any questions?
3y is the answer<span>.</span>
Answer:
(A) Yes, since the test statistic is in the rejection region defined by the critical value, reject the null. The claim is the alternative, so the claim is supported.
Step-by-step explanation:
Null hypothesis: The wait time before a call is answered by a service representative is 3.3 minutes.
Alternate hypothesis: The wait time before a call is answered by a service representative is less than 3.3 minutes.
Test statistic (t) = (sample mean - population mean) ÷ sd/√n
sample mean = 3.24 minutes
population mean = 3.3 minutes
sd = 0.4 minutes
n = 62
degree of freedom = n - 1 = 62 - 1 = 71
significance level = 0.08
t = (3.24 - 3.3) ÷ 0.4/√62 = -0.06 ÷ 005 = -1.2
The test is a one-tailed test. The critical value corresponding to 61 degrees of freedom and 0.08 significance level is 1.654
Conclusion:
Reject the null hypothesis because the test statistic -1.2 is in the rejection region of the critical value 1.654. The claim is contained in the alternative hypothesis, so it is supported.
Answer:
7
Step-by-step explanation:
7-7=0 and this cannot happen in the denominator
There are 30-18 = 12 girls. Their percentage is
... 12/30 × 100% = 40%
A + (b + c) = (a + b) + c.....what u have here is the associative property of addition
