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3 years ago

Paul bought : student discount card for the bus. The card allows him to buy daily bus passes for $1.40.

Mathematics

1 answer:

tekilochka [14]3 years ago

8 0

Paul spend 22.4 on student discount card.

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PLEASE HELP!!! WILL MARK AS BRAINLISTS!!!

Veseljchak [2.6K]

Answer:

vertical asymptote is: x=4

horizontal asymptote is: y=1

pls mark as brainliest :)

6 0

3 years ago

Andrei's grandfather offered to give him a gift at 50% of the amount of money he saved in one year. Andrei saved $120 dollars. H

Dafna1 [17]

Answer:

$60

Step-by-step explanation:

$120/2(half) = $60

3 0

3 years ago

Read 2 more answers

40 x 125% step it out

AlladinOne [14]

Answer:

0.50 or 50%

Step-by-step explanation:

40 x 125 = X

1.25 as a decimal or 125%

40 x 1.25 = 0.50

0.50 --->50%

40 x 125% = 50%

3 0

2 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago

6 more than a number w is 2

never [62]

Given a number w, six more than that number is $w+6$ . If you want this result to be 2, you have

$w+6=2$

Subtract 6 from both sides to get

$w = 2-6=-4$

3 0

3 years ago