Answer:
Side lengths = 1.68 ft and width = 3.36 ft.
Step-by-step explanation:
Let the side lengths of the window be L and the width = 2r ( r is also the radius of the semi-circle).
So we have
Perimeter = 2L + 2r + πr = 12
Area = 2rL + 0.5πr^2
From the first equation
2L = 12 - 2r - πr
Substitute for 2L in the equation for the area:
A = r(12 - 2r - πr) + 0.5πr^2
A = 12r - 2r^2 - πr^2 + 0.5πr^2
A = 12r - 2r^2 - 0.5πr^2
We need to find r for the maximum area:
Finding the derivative and equating to zero:
A' = 12 - 4r - πr = 0=
4r + πr = 12
r = 12 / ( 4 + π)
r = 1.68 ft.
So the width of the window = 2 * 1.68 = 3.36 ft.
Now 2L = 12 - 2r - πr
= 12 - 2*1.68 - 1.68π
= 3.36
L = 1.68.
Answer:
B and D
Step-by-step explanation:
10x^2 -vx [ has the highest power of X as 2 , so it is to degree 2].
6x^2 - 6x + 5[ has the highest power of x as 2; hence it is to degree 2]
The nearest meter is 4 meters because the 7 would round the 3 to a 4, but a 4 wouldn't round up the 2. Even if the 4 rounded up the 2 to a 3, it still wouldn't be enough to round the 4 up to a 5. In other words, 4 and below will not round up anything, but a 5 or above will round up anything (as far as basics go).
Answer:42x
Step-by-step explanation:
