All categories

3 years ago

Please help!!!! :)))))))

Mathematics

2 answers:

Tanzania [10]3 years ago

8 0

Answer:

10 units

Step-by-step explanation:

1. Do the square in the middle

2 x 2 = 4

2. Do the triangle on the left

2 x 2 divided by 2 = 2

3. Do the triangle on the right

4 x 2 divided by 2 = 4

4. Add them all up

4 + 2 + 4 = 10

sergiy2304 [10]3 years ago

7 0

10 units

Hopes this helps :)

You might be interested in

John worked x hours this week and shanique worked eight hours less than john. Write an algebraic expression for the number of ho

Allisa [31]

Answer is D because I watched a yt bidoe

3 0

3 years ago

Help me on 4. Please, I will be answering questions while I wait :)

FinnZ [79.3K]

8:4
8 to 4
8/4

:D :D :D

4 0

4 years ago

Read 2 more answers

I need help on this question

egoroff_w [7]

Answer:

29.52

Step-by-step explanation:

A=9.4*3.14

multiply and get 29.516

round to the nearest hundredth.

29.52

4 0

3 years ago

Find [5(cos 330 degrees + I sin 330 degrees)]^3

earnstyle [38]

Given a complex number in the form:
$z= \rho [\cos \theta + i \sin \theta]$
The nth-power of this number, $z^n$ , can be calculated as follows:

- the modulus of $z^n$ is equal to the nth-power of the modulus of z, while the angle of $z^n$ is equal to n multiplied the angle of z, so:
$z^n = \rho^n [\cos n\theta + i \sin n\theta ]$
In our case, n=3, so $z^3$ is equal to
$z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]$ (1)
And since
$3 \cdot 330^{\circ} = 990^{\circ} = 2\pi +270^{\circ}$
and both sine and cosine are periodic in $2 \pi$ , (1) becomes
$z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]$

6 0

4 years ago

So I need 20 words but I don’t get why so here’s this useless sentence

jek_recluse [69]

14(10) + 2, 14x10 is 140 plus 2 = 142
2(7(10) + 1) 7x10 = 70 + 1 = 2(71) = 142

8 0

3 years ago