The probability that only one shows a 2.
There are 36 different outputs (6x6) = 36
There are 6 combinations where the first cube shows a 2, these are 2,1;2,2;2,3;2,4;2,5; and 2.6
There are 6 combinations where the second cube shows a 2: 1,2;2,2;3,2;4,2;5,2; and 6,2.
Of those one combination on each set shows two 2.
Then the number of combinations with only one 2 are 6 - 1 + 6 -1 = 10
Now the probabilit is 10 out of 36 = 10 / 36 = 5 / 18
Answer: 505
Step-by-step explanation:
The formula to find the sample size n , if the prior estimate of the population proportion (p) is known:
, where E= margin of error and z = Critical z-value.
Let p be the population proportion of crashes.
Prior sample size = 250
No. of people experience computer crashes = 75
Prior proportion of crashes 
E= 0.04
From z-table , the z-value corresponding to 95% confidence interval = z=1.96
Required sample size will be :
(Substitute all the values in the above formula)
(Rounded to the next integer.)
∴ Required sample size = 505
72 m^2 (72 meters squared)
Answer:
length, width, height, volume
Step-by-step explanation:
Dave pays $15 and tax is $1.2 so dave spent a total of $16.20.
Mel pays $20 and tax is $1.6 so Mel spent a total of $21.60.
All you need to do is convert the percent to a decimal, so take 8 and divide by 100 and you get 0.08. then you need to multiply the cost by the tax so 15*0.08=1.2 then you just add tax to original amount 15+1.2=16.2
:)
