The answer to this question is 8 that's the answrb
If we solve the equations x-2y=5 and 4x+12y=-20 then we will get x=1 and y=-2.
Given two equations x-2y=5 and 4x+12y=-20.
We are required to find the value of x and y through substitution method.
Equation is like a relationship between two or more variables expressed in equal to form. Equations of two variables look like ax+by=c. Equation can be a linear equation,quadratic equation, cubic equation or many more depending on the power of variable.
They can be solved as under:
x-2y=5---------------1
4x+12y=-20--------2
Finding value of variable x from equation 1.
x=5+2y--------------3
Use the value of variable x in equation 2.
4x+12y=-20
4(5+2y)+12y=-20
20+8y+12y=-20
20y=-20-20
20y=-40
y=-40/20
y=-2
Use the value of variable y in equation 3.
x=5+2y
x=5+2*(-2)
x=5-4
x=1
Hence if we solve the equations x-2y=5 and 4x+12y=-20 then we will get x=1 and y=-2.
Question is incomplete as it should include one more equation x-2y=5.
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Answer:
Option (2)
Step-by-step explanation:
To solve this question we will use the property of tangents drawn to a circle.
"Tangents drawn from an external point to a circle are equal in length"
From the figure attached,
In ΔDEF,
DA = DC = 14 units [Equal tangents]
EA = EB = 13.7 units [Equal tangents]
FB = FC = 9 units [Equal tangents]
Therefore, DE = DA + AE = 14 + 13.7 = 27.7 units
EF = EB + BF = 13.7 + 9 = 22.7 units
DF = DC + FC = 14 + 9 = 23 units
Perimeter of ΔDEF = DE + EF + DF
= 27.7 + 22.7 + 23
= 73.4 units
Option (2) will be the answer.
Terms: 8p, 2q, 7r
coefficients: 8, 2, 7
