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2 years ago

Fabian bought 223 feet of wood to build

Mathematics

1 answer:

PilotLPTM [1.2K]2 years ago

5 0

Answer:

111 boxes

Step-by-step explanation:

He bought 223 feet of wood

Each box will take 2 feet

To determine the total number of box he'll make from 223,

1 box = 2 feet of wood

X box = 223 feet of wood

X = (223 × 1) / 2

X = 111.5 box approximately 112 boxes

But technically, since its 111.5, he'll be able to make 111 boxes completely with 0.5 feet of wood left

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Question 2 (multiple choice)

castortr0y [4]

Your x-intercept is at (-2,0) and your y intercept at (0,-3), so it's D

4 0

2 years ago

Pls answer asap, show work pls :(

coldgirl [10]

Answer:

2.Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form: ( 3 , 5 )

Equation Form: x = 3 , y = 5

3.Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form: ( 2 , 8 )

4.Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form: ( 2 , − 3 )

Step-by-step explanation:

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3 years ago

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.