Question

Six Hatfields and two McCoys are up for 3 construction jobs in Williamson. What is the probability that all 3 jobs go to Hatfields? Answer in decimal form. Round to 3 decimal places as needed. Your Answer:

Answer 1

Answer: 0.357

Step-by-step explanation:

Given : The number of Hatfield  = 6

The number of McCoys = 2

The number of companies = 8

The number of construction jobs -3

Now, the required probability is given by :-

$\dfrac{^6C_3\times^2C_0}{^8C_3}\\\\=\dfrac{\dfrac{6!}{3!(6-3)!}}{\dfrac{8!}{3!(8-3)!}}=0.357142857143\approx0.357$

Hence, the probability that all 3 jobs go to Hatfields =0.357