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maw [93]
3 years ago
10

Six Hatfields and two McCoys are up for 3 construction jobs in Williamson. What is the probability that all 3 jobs go to Hatfiel

ds? Answer in decimal form. Round to 3 decimal places as needed. Your Answer:
Mathematics
1 answer:
Fiesta28 [93]3 years ago
8 0

Answer: 0.357

Step-by-step explanation:

Given : The number of Hatfield  = 6

The number of McCoys = 2

The number of companies = 8

The number of construction jobs -3

Now, the required probability is given by :-

\dfrac{^6C_3\times^2C_0}{^8C_3}\\\\=\dfrac{\dfrac{6!}{3!(6-3)!}}{\dfrac{8!}{3!(8-3)!}}=0.357142857143\approx0.357

Hence, the probability that all 3 jobs go to Hatfields =0.357

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URGENT ANSWER NOW In △ABC, A=59∘, a=20, and c=21. What are the two possible values for angle C to the nearest tenth of a degree?
PilotLPTM [1.2K]

Answer:

The two possible values of C are 64.2° and 115.8°

Step-by-step explanation:

* In ΔABC

- a, b, c are the lengths of its 3 sides, where

# a is opposite to angle A

# b is opposite to angle B

# c is opposite to angle C

- m∠A = 59°

- a = 20

- c = 21

* To find the distance m∠C we can use the sin Rule

- In any triangle the ratio between the length of each side

 to the measure of each opposite angle are equal

- c/sinC = a/sinA = b/sinB

* Lets use it to find the m∠C

∵ 21/sinC = 20/sin(59)

∴ sin(C) = 21 × sin(59) ÷ 20 = 0.9000256657

∴ m∠C = sin^-1(0.9000256657)  = 64.16144°

∴ m∠C = 64.2°

∵ The value of sin(C) is positive

∴ Angle C may be in the first quadrant (acute angle)

  or in the second quadrant (obtuse angle)

∴ The other measure of ∠C = 180 - 64.2 = 115.8

* The two possible values of C are 64.2° and 115.8°

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