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scoundrel [369]
4 years ago
10

Find the sum of the arithmetic series 28+28.4+...+42

Mathematics
1 answer:
stira [4]4 years ago
8 0
23.6
Thyyhggghhhhnnnnn
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Find the circumference of the circle with the given radius or diameter. (Use 3.14 for it) r=20
iogann1982 [59]

Answer:

C = 2πr = 2 * 3.14 * 20 = 125.6

4 0
3 years ago
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Which of the following inequalities is best represented by this graph?
larisa86 [58]
#3. Plugging the point (3,0) into any of the equations except the third one gives an invalid answer. 
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3 years ago
1 Point<br> The circle below is centered at (-3, 2) and has a radius of 3. What is its<br> equation?
arlik [135]

Answer:

(x + 3)^2 + (y - 2)^2 = 9

Step-by-step explanation:

<u>Equation for a circle:  (x – h)^2 + (y – k)^2 = r^2</u>

<u />

<u>Step 1:  Determine what h, k, and r are</u>

<em>h is the x value of the point:  -3</em>

<em>k is the y value of the point:  2</em>

<em>r is the radius of the circle:  3</em>

<u>Step 2:  Plug in and solve</u>

(x – h)^2 + (y – k)^2 = r^2

(x – (-3))^2 + (y – (2))^2 = (3)^2

<em>(x + 3)^2 + (y - 2)^2 = 9</em>

<em />

Answer:  (x + 3)^2 + (y - 2)^2 = 9

8 0
4 years ago
A simplified model of the human blood-type system has four blood types: A, B, AB, and O. There are two antigens, anti-A and anti
dexar [7]

Answer: Blood type will be A when event "A" happened and event "B" did not happen. Blood type will be B when event "A" did not happened and event "B" happened. Blood type will be AB when both events happened and blood type will be O when both events did not happen.

Step-by-step explanation:

S={AntiA reacts; AntiA does not react; AntiB reacts; AntiB does not react}

If AntiA reacts and AntiB reacts = AB (A∩B)

If AntiA does not react and AntiB does not react= O (A'∩B')

If AntiA reacts and AntiB does not react= A (A∩B')

If AntiA does not react and AntiB reacts= B (A'∩B)

4 0
4 years ago
12 cos theta minus 16 sin theta is equal to zero find 2 sin theta + cos theta​
gayaneshka [121]

Answer:

2sinθ + cosθ = 2

Step-by-step explanation:

12 cos θ - 16 sinθ = 0

=> 3 cos θ -4 sin θ = 0

=> tanθ = 3/4

let P = 3x

B = 4x

=> H= 5x

=> sinθ = P/H = 3/5

cosθ = B/H = 4/5

2sinθ + cosθ

= 2× 3/5 + 4/5

= 6/5+4/5

= 10/5

= 2

=> 2sinθ + cosθ = 2

5 0
3 years ago
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