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3 years ago

Justin did push-ups for the past 5 days. The following data points are the number of push-ups he did each day.

Mathematics

2 answers:

ohaa [14]3 years ago

8 0

Answer:

The standard deviation is approximately 2.76 push-ups.

Step-by-step explanation:

irga5000 [103]3 years ago

6 0

Answer:

2.67

Step-by-step explanation:

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Order of operations

timurjin [86]

Answer:

z+9(8−x)+8(z+8)=

z+72-9x+8z+64=

9z-9x+136

(3−10)^2−(5−12)^2 parenthesis first

(-7)²-(-7)²=

49-(49)=49-49=0

2^2⋅4^3 exponent first

2*2*4*4*4

4*64=256

6 0

2 years ago

Help!!!!!!!!!!!!!!!!!!!

nata0808 [166]

Answer:

Six planes are shown

Step-by-step explanation:

Hope that helps

3 0

2 years ago

Read 2 more answers

Which property is shown by -3 x (6+5) = -3 x 6+ -3 x 5

aniked [119]

Answer:

The distributive property of multiplication

Step-by-step explanation:

we know that

The distributive property of multiplication states that the product of a number by a sum, is equal to multiply each addend by the number (This is called distributing the number) and then, you can add the products

$a*(b+c)=a*b+a*c$

in this problem we have

$-3*(6+5)=-3*6+-3*5$ ----> the number -3 is distributed

therefore

We have the distributive property of multiplication

4 0

3 years ago

The base of the triangle is 5<img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D" id="TexFormula1" title="\sqrt{3}" alt="\sqrt{3}"

Vsevolod [243]

Answer:

yes you are absolutely right

it will be the answer

4 0

2 years ago

Kamal wrote the augmented matrix below to represent a system of equations

ra1l [238]

Consider the operation is $R_2\to -3R_2$ .

Given:

The augmented matrix below represents a system of equations.

$\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]$

To find:

Matrix results from the operation $R_2\to -3R_2$ .

Step-by-step explanation:

We have,

$\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]$

After applying $R_2\to -3R_2$ , we get

$\left[\left.\begin{matrix}1&0&1\\-3(1)&-3(3)&-3(-1)\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-3(-9)\\-2\end{matrix}\right]$

$\left[\left.\begin{matrix}1&0&1\\-3&-9&3\\3&2&0\end{matrix}\right|\begin{matrix}-1\\27\\-2\end{matrix}\right]$

Therefore, the correct option is A.

3 0

2 years ago