Ask question

Ask question

All categories

3 years ago

12

A window in Michael's room is the shape of a trapezoid. The bases are 30 inches and 40 inches. The height of the window is 24 in

ches. Find the area of the window.

1 answer:

lana [24]3 years ago

3 0

Answer:

The area of the window is of 840 square inches.

Step-by-step explanation:

To find the area of an trapezoid, we need to add the sum of the bases, multiply by the height, and then divide by 2.

Matematically:

$A = \frac{(b_{1} + b_{2})*h}{2}$

In which $b_{1}$ and $b_{2}$ are the bases and h is the height.

In this question:

$b_{1} = 30, b_{2} = 40, h = 24$

All the measures in inches, so the area is in square inches.

$A = \frac{(30 + 40)*24}{2} = 840$

The area of the window is of 840 square inches.

You might be interested in

Gelneren [198K]

Answer:

General equation of line : $y = mx+c$ --1

Where m is the slope or unit rate

Table 1)

p d

1 3

2 6

4 12

d = Number of dollars (i.e.y axis)

p = number of pound(i.e. x axis)

First find the slope

First calculate the slope of given points

$m = \frac{y_2-y_1}{x_2-x_1}$ ---A

$(x_1,y_1)=(1,3)$

$(x_2,y_2)=(2,6)$

Substitute values in A

$m = \frac{6-3}{2-1}$

$m = 3$

Thus the unit rate is 3 dollars per pound.

So, It matches the box 1 (Refer the attached figure)

Equation 1 : $p=3d$

$\frac{p}{3}=d$

Since p is the x coordinate and d is the y coordinate

On Comparing with 1

$m = \frac{1}{3}$

Thus the unit rate is $\frac{1}{3}$ dollars per pound

So, It matches the box 2 (Refer the attached figure)

Equation 2 : $\frac{1}{3}d=3p$

$d=9p$

Since p is the x coordinate and d is the y coordinate

On Comparing with 1

$m =9$

Thus the unit rate is 9 dollars per pound

So, It matches the box 3 (Refer the attached figure)

Table 2)

p d

1/9 1

1 9

2 18

d = Number of dollars (i.e.y axis)

p = number of pound(i.e. x axis)

$(x_1,y_1)=(\frac{1}{9},1)$

$(x_2,y_2)=(1,9)$

Substitute values in A

$m = \frac{9-1}{1-\frac{1}{9}}$

$m = \frac{8}{frac{8}{9}}$

$m = 9$

Thus the unit rate is 9 dollars per pound

So, It matches the box 3 (Refer the attached figure)

3 0

3 years ago

Read 2 more answers

-1/225x^2+2/3x what is the vertex of this quadratic function?

Julli [10]

$\bf \textit{vertex of a parabola}\\ \quad \\\\

\begin{array}{lccclll}
y=&-\frac{1}{225}x^2&+\frac{2}{3}x\\\\
y=&-\frac{1}{225}x^2&+\frac{2}{3}x&+0\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$

6 0

3 years ago

2) When we divide ______ by 8 gives a quotient of 75 and a remainder of 3

Pani-rosa [81]

Answer:

603

Step-by-step explanation:

603/8

600/8 + 3/8 = 75, 3/8

4 0

3 years ago

Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti

almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

$d=v.t$

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

$d=(x+y).t_1$

Where t1=2.5 hours. Substituting values:

$20=(x+y)*2.5$

Rearranging, we find the downstream equation:

$2.5x+2.5y=20\qquad[1]$

The speed when rowing upstream is x-y, and the distance traveled is

$d=(x-y).t_2$

Where t2=5 hours. Substituting values:

$20=(x-y)*5$

Rearranging, we find the upstream equation:

$5x-5y=20\qquad[2]$

Multiplying [1] by 2:

$5x+5y=40$

Adding this equation to [2]:

$10x=60$

Solving:

$x=60/10=6$

Dividing [2] by 5:

$x-y=4$

Solving for y

$y=x-4=6-4=2$

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

3 0

3 years ago

Which angles are coterminal with an angle drawn in standard position measuring 282°?

vampirchik [111]

Answer:

−438°, -78°, 642°

Step-by-step explanation:

Given angle:

282°

To find the co-terminal angles of the given angle.

Solution:

Co-terminal angles are all those angles having same initial sides as well as terminal sides.

To find the positive co-terminal of an angle between 360°-720° we will add the angle to 360°

So, we have: $282\°+360\°=642\°$

To find the negative co-terminal of an angle between 0° to -360° we add it to -360°

So, we have: $282\°-360\°=-78\°$

To find the negative co-terminal of an angle between -360° to -720° we add it to -720°

So, we have: $282\°-720\°=-438\°$

Thus, the co-terminal angles for 282° are:

−438°, -78°, 642°

7 0

3 years ago