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2 years ago

15

What is the positive square root of 9/16

2 answers:

vovangra [49]2 years ago

7 0

Answer: |√9/16| = ¾ or .75

PLz mark brainliest:)

lilavasa [31]2 years ago

5 0

I think the answer is .75:)

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Between the time Iko woke up and lunchtime,the temperature rose by 11.Then by the time he went to bed,the temperature dropped by

dimaraw [331]

Answer:

<u></u>

<u>11 + ( - 14)</u>

Explanation:

The complete question is:

<em>Between the time iko woke up and lunchtime, the temperature rose by 11º. Then by the time he went to bed, the temperature dropped by 14º.</em>

<em />

<em>Write an addition expression for the temperature relative to when iko woke up. </em>

<em />

<h2>Solution</h2>

It is said that between the time Iko woke up and lunchtime, the temperature rose by 11 degrees. A rise means the temperature increased and you must add 11º.

Then, relative to when Iko woke up the temperature is:

+ 11º

Then, by the time Iko went to bed, the temperature dropped by 14º. A drop means that the change is negative. This means that you must add a negative number, and the additive expression is:

+ 11º + (- 14º).

If you want the overall change in temperature you do the operation:

11 + (-14) = 11 - 14 = - 3. A net decrease of 3º.

But the answer to this question is the additive expression:

11 + ( - 14) ← answer

4 0

3 years ago

Which describes the motion shown?

ra1l [238]

Answer:

A.)

Step-by-step explanation:

7 0

2 years ago

Wren and Jenni are reading the same book. Wren is on page 12 and reads 7 pages every night. Jenni is on page 8 and reads 11 page

Igoryamba

You should make a table

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2 years ago

4.5 - d > 2.5 substitute 2.5 for d

den301095 [7]

Answer:

so whats the question?

Step-by-step explanation:

5 0

2 years ago

The slope f′(x) at each point (x,y) on a curve y=f(x) is given, along with a point (a,b) on the curve. Use this information to f

Montano1993 [528]

$f'(x)=\dfrac{4x}{1+7x^2}$

Integrating gives

$f(x)=\displaystyle\int\frac{4x}{1+7x^2}\,\mathrm dx$

To compute the integral, substitute $u=1+7x^2$ , so that $\frac27\,\mathrm du=4x\,\mathrm dx$ . Then

$f(x)=\displaystyle\frac27\int\frac{\mathrm du}u=\frac27\ln|u|+C$

Since $u=1+7x^2>0$ for all $x$ , we can drop the absolute value, so we end up with

$f(x)=\dfrac27\ln(1+7x^2)+C$

Given that $f(0)=10$ , we have

$10=\dfrac27\ln1+C\implies C=10$

so that

$\boxed{f(x)=\dfrac27\ln(1+7x^2)+10}$

7 0

3 years ago