All categories

3 years ago

How do you find the surface area of a octahedron

1 answer:

6 0

If it's a regular octahedron, then you can calculate it using the formula $2\sqrt3a^2$ where $a$ is the length of the edge.
If it's not regular, you have to calculate the area of each side individually.

You might be interested in

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

2 years ago

The Hunters drove to visit some friends. The table below shows how long it 1 point

Leni [432]

Answer:

60 miles per hour

Step-by-step explanation:

For each point just divide the miles by the hour

120/2 = 60 mph

180/3 = 60 mph

240/4 = 60 mph

7 0

3 years ago

Find the surface area of the square pyramid 8mm 6mm

bija089 [108]

Answer:

136 mm²

Step-by-step explanation:

$A=a^{2} +2a\sqrt{\frac{a^{2} }{4} } +h^{2}$

$A=6^{2} +2(6)\sqrt{\frac{6^{2} }{4} } +8^{2}$

$A=36 +12\sqrt{\frac{36 }{4} } +64$

$A=36 +12\sqrt{9 } +64$

$A=36 +12(3)+64$

$A=36 +36+64$

A = 136

5 0

3 years ago

What is the sum of two consecutive even integers divided by four is 189.5?

mixas84 [53]

Let us denote the smaller even integer by $N$ .
Then, the next even integer must be $N+2$ .

To verify, set $N$ as any even number, say $174$ .
Then, the next even integer must be 2 more than this number, i.e. $174+2=176$ .

The sum of these two consecutive even integers can be expressed as:
                                    $N+(N+2)=2N+2$

We are told that this sum divided by four is 189.5, i.e.
                                     $(2N+2)\div4=189.5$

Multiplying both sides by 4 will reverse the division:
     $(2N+2)\div4\times4=189.5\times4$
     $(2N+2)\times1=758$

Subtracting 2 from each side will reverse the addition:
     $2N+2-2=758-2$
     $2N=756$

Dividing both sides by 2 will reverse the multiplication:
     $2N\div2=756\div2$
     $N=378$

Therefore, the two consecutive integers must be 378 and 380.

Check this:
     $(378+380)\div4=758\div4=189.5$

3 0

3 years ago

1. You withdraw $17 from your account.

melisa1 [442]

D) elimainate only. WHY? Well it best represents the scenes of events in time and place defenetly that.

7 0

3 years ago