Answer:
21.8 m/s
Step-by-step explanation:
Given that Tom drops a object from a height of <em>h </em>meters and it hits the ground with a veloc8of <em>v </em><em>m/</em><em>s </em>and it is given by function ;
We need to find out the velocity upon reaching the ground when it is dropped from a height of 24.3 m . On plugging in 24.3 in place of h we have ,
And we are done !
Sin 20° · sin 40° · sin 80° = 1/2 ( cos 20° - cos 60° ) · sin 80° =
= 1/2 ( cos 20° sin 80° - cos 60° sin 80° ) =
= 1/2 ( (sin 100° + sin 60°)/2 - 1/2 sin 80° )= ( sin 100° = sin 80° )
= 1/2 · ( 1/2 sin 60° ) = 1/4 sin 60° = √3 / 8
sin 60° = √ 3/2
√ 3 / 2 · √ 3 / 8 = 3/16 ( correct )
Answer:
Step-by-step explanation:
I think yes maybe.....................
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Answer:
See below
Step-by-step explanation:
Basically, when you have a product to two factors set equal to 0, you can use the Zero Product Property and make two separate equations, both set equal to 0, to find the roots for each factor:
Notice that by plugging these roots back into the equation, either factor will be 0, making the whole expression 0:
