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Bumek [7]
3 years ago
10

In Amy’s backyard, there are also chickens and rabbits. There are 5 more chickens than rabbits. The total number of legs is 130.

How many rabbits and how many chickens?
Mathematics
1 answer:
Butoxors [25]3 years ago
3 0

Answer:

There are 25 chickens and 20 rabbits

Step-by-step explanation:

Let

x-----> the number of chickens

y ----> the number of rabbits

Remember that

1 chicken has two legs

1 rabbit has four legs

so

2x+4y=130 -------> equation A

x=y+5 -----> equation B

Substitute equation B in equation A and solve for y

2(y+5)+4y=130

2y+10+4y=130

6y=120

y=20 rabbits

Find the value of x

x=y+5

x=20+5=25 chickens

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nika2105 [10]

Answer:

X \sim Binom(n=12, p=0.4)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X=3)=(12C3)(0.4)^3 (1-0.4)^{12-3}=0.14189

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=12, p=0.4)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X=3)=(12C3)(0.4)^3 (1-0.4)^{12-3}=0.14189

3 0
3 years ago
water has a freezing point of 32°F mercury has a freezing point that is 70°F lower. what us the freezing ponit of mercury​
Sonja [21]
-38 degrees fahrenheit
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Which of the formulas below could be a polynomial with all of the following properties: its only zeros are x = -6, -2, 2, it has
VARVARA [1.3K]

Answer:

A, B, and E

if I read your functions right.

Step-by-step explanation:

It's zeros are x=-6,-2, and 2.

This means we want the factors (x+6) and (x+2) and (x-2) in the numerator.

It has a y-intercept of 4.  This means we want to get 4 when we plug in 0 for x.

And it's long-run behavior is y approaches - infinity as x approaches either infinity.  This means the degree will be even and the coefficient of the leading term needs to be negative.

So let's see which functions qualify:

A) The degree is 4 because when you do x^2*x*x you get x^4.

The leading coefficient is -4/144 which is negative.

We do have the factors (x+6), (x+2), and (x-2).

What do we get when plug in 0 for x:

\frac{-4}{144}(0+6)^2(0+2)(0-2)

Put into calculator:  4

A works!

B) The degree is 6 because when you do x*x^4*x=x^6.

The leading coefficient is -4/192 which is negative.

We do have factors (x+6), (x+2), and (x-2).

What do we get when we plug in 0 for x:

\frac{-4}{192}(0+6)(0+2)^4(x-2)

Put into calculator: 4

B works!

C) The degree is 4 because when you do x*x*x*x=x^4.

The leading coefficient is -4 which is negative.

Oops! It has a zero at 0 because of that factor of (x) between -4 and (x+6).

So C doesn't work.

D) The degree is 3 because x*x*x=x^3.

We needed an even degree.

D doesn't work.

E) The degree is 4 because x*x^2*x=x^4.

The leading coefficient is -4/48 which is negative.

It does have the factors (x+6), (x+2), and (x-2).

What do we get when we plug in 0 for x:

\frac{-4}{48}(0+6)(0+2)^2(0-2)

Put into calculator: 4

So E does work.

F) The degree is 4 because x*x*x^2=x^4.

The leading coefficient is -4/48.

It does have factors (x+6), (x+2), and (x-2).

What do we get when we plug in 0 for x:

\frac{-4}{48}(0+6)(0+2)(0-2)^2

Put into calculator: -4

So F doesn't work.

G. I'm not going to go any further. The leading coefficient is 4/48 and that is not negative.

So G doesn't work.

4 0
3 years ago
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How many solutions are there in 1/2 (10x + 15) – 3/2 = 2x + 6 + 3x
goldenfox [79]

Answer:

Value for x cannot be deduced

Step-by-step explanation:

To solve this question we will have to open the bracket first...we will solve using bodmas rule

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Open the bracket

5x+5/2-3/2=2x+6+3x

Let's collect the like terms

5x-2x-3x=6-5/2+3/2

Lcm for the right side is 2

0=12-5+3/2

0=10/2

0=5

Therefore the value for x cannot be deduced due to the fact that x has been cancelled when solving

4 0
3 years ago
Plz help I don’t understand
adell [148]
So Kalinda starts with $25. Then she spends $14.28. This means you subtract since she spends it. Next, she shares $2.65. Again, use subtraction. The remainder is your answer. Or you can add 14.28 to 2.65 and then subtract that from 25.
3 0
3 years ago
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