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pshichka [43]
3 years ago
12

Help please please 100pts no trolls please

Mathematics
2 answers:
ycow [4]3 years ago
8 0

Answer:

21.8 m/s

Step-by-step explanation:

Given that Tom drops a object from a height of <em>h </em>meters and it hits the ground with a veloc8of <em>v </em><em>m/</em><em>s </em>and it is given by function ;

\longrightarrow v =\sqrt{19.6h}

We need to find out the velocity upon reaching the ground when it is dropped from a height of 24.3 m . On plugging in 24.3 in place of h we have ,

\longrightarrow v =\sqrt{19.6\times 24.3 }\ m/s\\\\\longrightarrow v =\sqrt{ 476.28} m/s \\\\\longrightarrow v = 21.823 \ m/s \\\\\longrightarrow \underline{\underline{ v = 21.8 \ m/s }}

And we are done !

algol [13]3 years ago
7 0

Answer:

<u>21.8</u>

Step-by-step explanation:

The formula is given :

  • v = √(19.6h)

Given that h = 24.3 m, we need to find v.

Substituting the value of h in the formula :

  • v = √(19.6)(24.3)
  • v = √476.28
  • v = <u>21.8</u> m/s (nearest tenth)
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During the first hour of operation the farm stand owner sold 15% of the apples he had. On the second hour he sold 20% of the rem
liraira [26]

Answer:

 3.825 kg apples.

Step-by-step explanation:

Let x kg be the amount of apples stand owner had initially.

We have been given that during the first hour of operation the farm stand owner sold 15% of the apples he had. Then the amount of sold apples will be:

\text{The amount of sold apples during 1st hour}=\frac{15}{100}x=0.15x

\text{The amount of remaining apples after 1st hour}=x-0.15x

\text{The amount of remaining apples after 1st hour}=0.85x

On the second hour he sold 20% of the remaining apples. So the amount of sold apples on the second hour will be 20% of 0.85x.

\text{The amount of sold apples during 2nd hour}=0.85x*\frac{20}{100}  

\text{The amount of sold apples during 2nd hour}=0.85x\times 0.20  

\text{The amount of sold apples during 2nd hour}=0.17x

During the second hour 25.5 kg of apples were sold, so we can set up an equation as:

25.5=0.17x

\frac{25.5}{0.17}=\frac{0.17x}{0.17}

150=x

So, stand owner had initially 150 kg of apples.

\text{The amount of remaining apples after 2nd hour}=0.85x-0.17x

\text{The amount of remaining apples after 2nd hour}=0.68x

On the third hour he sold 25% of the remaining apples. So the amount of sold apples on the 3rd hour will be 25% of 0.68x

\text{The amount of sold apples during 3rd hour}=0.68x*\frac{25}{100}

\text{The amount of sold apples during 3rd hour}=0.68x*0.25

\text{The amount of sold apples during 3rd hour}=0.17x  

\text{The amount of remaining apples after 3rd hour}=0.68x-0.17x

\text{The amount of remaining apples after 3rd hour}=0.51x

As remaining apples were sold 5% more each following hour.

\text{The amount of sold apples during 4th hour}=0.51x*\frac{5}{100}

\text{The amount of sold apples during 4th hour}=0.51x*0.05

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Let us substitute x=150 into above equation we will get,

\text{The amount of sold apples during 4th hour}=0.0255*150

\text{The amount of sold apples during 4th hour}=3.825

Therefore, 3.825 kg of apples were sold during the 4th hour.

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3 years ago
Median of 28, 30, 34, 35
Arturiano [62]
You first put them all in order from least to greatest. Now, since 30 and 34 seem to be in the middle, write the number in between them: 30, 31, 32, 33, 34.

And you get your answer as 32. Hope this helped ;)
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What is the positive root of the equation x2 + 5x = 150?<br> ao
fenix001 [56]

Answer:

10.

Step-by-step explanation:

x^2 + 5x = 150

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This equation will factor:

(x - 10)(x + 15) = 0

x - 10 = 0 or x + 15 = 0, so:

x = 10 or -15.

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artcher [175]

Answer:

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Step-by-step explanation:

3p+5=11

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