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Mathematics

2 answers:

ycow [4]2 years ago

8 0

Answer:

21.8 m/s

Step-by-step explanation:

Given that Tom drops a object from a height of h meters and it hits the ground with a veloc8of v m/s and it is given by function ;

$\longrightarrow v =\sqrt{19.6h}$

We need to find out the velocity upon reaching the ground when it is dropped from a height of 24.3 m . On plugging in 24.3 in place of h we have ,

$\longrightarrow v =\sqrt{19.6\times 24.3 }\ m/s\\\\\longrightarrow v =\sqrt{ 476.28} m/s \\\\\longrightarrow v = 21.823 \ m/s \\\\\longrightarrow \underline{\underline{ v = 21.8 \ m/s }}$

And we are done !

algol [13]2 years ago

7 0

Answer:

21.8

Step-by-step explanation:

The formula is given :

v = √(19.6h)

Given that h = 24.3 m, we need to find v.

Substituting the value of h in the formula :

v = √(19.6)(24.3)
v = √476.28
v = 21.8 m/s (nearest tenth)

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3 years ago

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Basile [38]

Answer:

$x=8\frac34\ \,,\quad y=8\frac12$

Step-by-step explanation:

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