Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or,
or,
or,
or,
Substituting the value of in ∠QPR we get,
∠QPR =
or, ∠QPR =
Hence,
The value of ∠QPR is 40°.
Answer:
540
Step-by-step explanation:
The answer of this question is 152
Answer:
see the procedure
Step-by-step explanation:
we know that
m∠1+m∠2=180° -----> supplementary angles (form a linear pair)
we have
m∠1=27° ----> given problem
substitute the measure of m∠1 in the equation above and solve for m∠2
27°+m∠2=180°
Subtract 27° both sides
27°+m∠2-27°=180°-27° ----> by subtraction property of equality
m∠2=153°