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3 years ago

13

The sum of two consecutive integers is 77. Find the integers.

2 answers:

SIZIF [17.4K]3 years ago

5 0

Answer:

38 and 39

Step-by-step explanation:

Since the two integers are consecutive, then one is one larger than the other. Therefore, lets call them x and x+1. We can now set up the following equation:

x+(x+1)=77

2x+1=77

2x=76

x=38

x+1=39

Hope this helps!

Rashid [163]3 years ago

5 0

Answer:I believe it is 39 and 38

Step-by-step explanation:

x + (x+1) = 77

2x = 76

x = 38 (1st number)

x+1 = 39 (2nd number)

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irinina [24]

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3 years ago

Read 2 more answers

What is the equation of the following graph?

nignag [31]

Answer:

${y}^{2} = 24x$

Step-by-step explanation:

This is horizontal parabola.

It has a directrix at x=-6.

The vertex is (0,0).

The focus is (6,0)

The equation of this parabola is of the form

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Where (p,0) is the focus

By comparison, p=6

Therefore the equation of the parabola is

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6 0

4 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

The square of a number is equal to two less than three times the number. What are two possible values of the number?

ycow [4]

Answer:

A, 1,2

Step-by-step explanation:

we translate it first into language of math

we use n for the number

n² = 3n - 2

then, do some algebra things

n² - 3n + 2 = 0

then factorize it

(n - 2)(n - 1) = 0

first n

n - 2 = 0

n = 2

2nd n

n - 1 = 0

n = 1

so n can be 1 or 2

4 0

4 years ago

Factorise<br> 24p2 + pq - 23q²

Novosadov [1.4K]

<em>24p² + pq - 23q² = </em>

<em>= 24p² + 24pq - 23pq - 23q²</em>

<em>= 24p(p + q) - 23q(p + q)</em>

<em>= (p + q)(24p - 23q)</em>

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3 0

3 years ago