To find the slope<span> and y </span>intercept<span>, use the </span><span>y=mx+b</span> formula<span> where </span>m<span> is the </span>slope<span> and </span>b<span> is the y </span>intercept<span>.
</span><span>y=mx+b
</span>Pull the values of m<span> and </span>b<span> using the </span><span>y=mx+b</span> formula<span>.
</span><span>m=<span>7/2</span>,</span><span>b=−2</span><span> where m is the </span>slope<span> and b is the </span>y-intercept
Answer:
c=4
Step-by-step explanation:
–2c = –c − 4
add c to both sides
-1c=-4
divide both sides by -1
c=4
Total liters of water needed = number of attendee x water consumption/attendee wherenumber of attendee = 7000 attendeewater consumption/attendee = 0.5litre of water/attendeetotal = 7000 x 0.5 litre = 3500 litrescomputing the water requirement per 200 litre containerwater requirement in the event = 3500 litres/200 litre /container = 17.5 containersThe water requirement in the event at the arena of 7000 attendees is 17.5 containers.
Answer: When the quadratic equation can be factored or solved by completing the square, you do not need to use the quadratic formula
Step-by-step explanation: In the form ax² + bx + c
Whenever <em><u>a</u></em> is 1 (implied, no coefficient of x²) and the constant, <u><em>c</em></u>, is a multiple of numbers whose sum or difference is equal to <u><em>b</em></u>, factoring is much quicker and easier than using the quadratic formula.
Even when there is a coefficient of x², there are procedures to find the factors and solve for x without resorting to the quadratic formula.
• Angles DXC and AXB form a vertical pair, so they are congruent and have the same measure.
• ∆ABD is isosceles, since it's given that AD and BD are congruent. This means the "base angles" BAD and ABD have the same measure; call this measure <em>x</em>.
• The measure of angle ADB can be computed by using the inscribed angle theorem, which says
m∠ADB = 1/2 (100°) = 50°
(that is, it's half the measure of the subtended arc AB whose measure is 100°)
• The interior angle to any triangle sum to 180° in measure. So we have in ∆ABD,
m∠ADB + 2<em>x</em> = 180°
Solve for <em>x</em> :
50° + 2<em>x</em> = 180°
2<em>x</em> = 130°
<em>x</em> = 65°
• Use the inscribed angle theorem again to find the measure of angle BAC. This will be half the measure of the subtended arc BC, so
m∠BAC = 1/2 (50°) = 25°
• Now in ∆ABX, we have
m∠AXB + 25° + 65° = 180°
m∠AXB = 90°
Hence m∠DXC = 90°.
