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Finger [1]
3 years ago
6

What is –2c = –c − 4

Mathematics
2 answers:
crimeas [40]3 years ago
6 0

Answer:

c=4

Step-by-step explanation:

–2c = –c − 4

add c to both sides

-1c=-4

divide both sides by -1

c=4

dedylja [7]3 years ago
6 0
–2c = –c − 4
Collect like terms and rearrange
-2c+c=-4
Sinplify
-c= -4
Divide “-“ by both sides
C=4
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brian bought X apples and some oranges. Brian bought 3 more oranges than apples. find the toal number of fruit brian bought in t
Sophie [7]


<span>We can make an equation through that information.
X+3+3
</span>Brian bought 3 more of the oranges and apples, and that will get you
X+3+3
=
X+6
 
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3 years ago
Fill in the box with the appropriate measure.<br> quick please I have only a few min left
Art [367]

Step-by-step explanation:

first box on the left

r=4

d=8

circumference= 2π*4= 8π

area = π*4*4= 16π

Second box on the left

d=6

r= 3

circumference= 2π*3= 6π

area =π*3*3= 9π

third box on the left

A=36π

A=36πarea= π*r*r

A=36πarea= π*r*rr= 6

A=36πarea= π*r*rr= 6d=12

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the last box

C=18π

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C=18πC= 2π*rr= 9

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C=18πC= 2π*rr= 9d=18area= π*9*9= 81π

8 0
2 years ago
The Eagle Club wants to build a chain of 2,505 dominoes. If they have already set up 807 dominoes, how many more do they need to
Sloan [31]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

8 0
3 years ago
PLEASE HELP FAST!!!
Leni [432]

Answer:

Hello,

I just think that it is A

Why you may ask?

Because it has a Zero and that is an undefined number than

Step-by-step explanation:

Please I want brainest

6 0
2 years ago
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