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Nataly_w [17]
3 years ago
8

Leah knit a scarf that is 130 centimetres ( cm ) long. Theo knit a scarf that is 4/3 as long Leah's scarf. How long is Theo's sc

arf?
Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

173.33333333333...

Step-by-step explanation:

4/3=1.3333333...

So 130×1.3333333... is 173.3333333...

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Jadas family has completed 30% of a trip. They have traveled 15 miles. How far is the trip
valentina_108 [34]

Answer:

50

Step-by-step explanation:

.3x=15

x=50

8 0
3 years ago
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Please help me with my math ;-;
Pachacha [2.7K]
I only know 1 & 4 .. 2 & 3 seem hard to me ..
X >7
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7 0
2 years ago
How many feet are in 9 meters? <br> 1 m = 3.3 ft<br><br><br>9 m = [?] ft​
sukhopar [10]
9 x 3.3 ft = 29.7 feet
8 0
3 years ago
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A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.
Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h(t)=-48t -16t^2. We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula x=-\frac{b}{2a}.

x=-\frac{-48}{2(-16)}

x=-\frac{48}{32}

x=-\frac{3}{2}

So, the x-coordinate of the parabola is -\frac{3}{2}. Now, we will substitute x=-\frac{3}{2} in our given equation to find y-coordinate of parabola.

h(t)=-48t -16t^2

h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2

h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})

h(-\frac{3}{2})=72-4*9

h(-\frac{3}{2})=72-36

h(-\frac{3}{2})=36

Therefore, the maximum height of the ball is 36 feet.

3 0
2 years ago
Find the line through
Kaylis [27]

Answer:

(\frac{1}{2},\frac{-1}{2},\frac{1}{2})

Step-by-step explanation:

We have been given the intersection coordinates:

(7,1,-6) and perpendicular to the line x=-1+t ,y=-2+t and z=-1+t

From the condition of perpendicularity we know:  

(7,1,-6)(x,y,z)

\Rightarrow 7x+y-6z=0

Now, we have given x=-1+t , y=-2+t and  z= -1+t

7(-1+t)+(-2+t)-6(-1+t)=0

-7+7t-2+t+6-6t=0

\Rightarrow -3+2t=0

2t=3

t=\frac{3}{2}

Now, substituting t in the given coordinates x,y and z we get:

x=-1+\frac{3}{2}=\frac{1}{2}

y=-2+\frac{3}{2}=\frac{-1}{2}

And z=-1+\frac{3}{2}=\frac{1}{2}



3 0
3 years ago
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