Answer:
0.395 kilometre
Step-by-step explanation:
Given:
On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole.
On his second stroke, the ball traveled 79 meters and went into the hole.
<u>Question asked:</u>
How many kilometres from the hole was Martin when he started?
<u>Solution:</u>
Let distance from Martin starting point to the hole in meters = 
On Martin's first stroke, ball traveled = 
On his second stroke, the ball traveled and went to the hole = 79 meters
Total distance from starting point to the hole = Ball traveled from first stroke + Ball traveled from second stroke
Now, convert it into kilometre:
1000 meter = 1 km
1 meter = 
395 meters = 
Thus, there are 0.395 kilometre distance from Martin starting point to the hole.
Answer:
P= 2
T=6
3) 252$
Step-by-step explanation:
1) set up your equation 3/8p=6/8 then divide 3/8 from both sides (remember when you divide fractions you would multiply by the reciprocal so 3/8 x 8/6. Also make sure you simplify)
2) Do the same here. 38/7 divided by 19/21
3) Turn the fraction into an improper fraction then multiply 126 by that amount (3/6)
Answer:
8x^8/3 y^4 - The first option
Step-by-step explanation:
The first thing we need to do is the exponent outside the bracket and leave the 8 till last, because exponents always come before multiplying coefficients. When an term with an exponent is multiplied by another exponent outside a bracket, the exponents of both terms are multiplied by the exponent outside the bracket.
This means that the expression is now:
8(x^2*4/3 y^3*4/3)
First we can so the x term. The x term already has an exponent of 2, so the 2 is multiplied by the 4/3 exponent outside the bracket. 2*4/3 = 8/3, so the x term is now: x^8/3
The same happens to the y term: 3*4/3 simplifies to 4, so the y term is now y^4.
So now our expression is:
8(x^8/3 y^4)
Now the 8 outside the bracket simply multiplies on to the whole term so we finish with:
8x^8/3 y^4 - The first option.
Hope this helped!
Answer:
The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Step-by-step explanation:
Let be 
, where 
is the stopping distance measured in metres and 
is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.
The procedure to find the speed related to the given stopping distance is described below:
1) Construct the graph of 
.
2) Add the function 
.
3) The point of intersection between both curves contains the speed related to given stopping distance.
In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
