<span>Using whole numbers, fractions, and decimals, these are the eight addition equations that have the sum of 10
</span>1. 5+5=10
2. 1 1/2 + 8 1/2 =10
3. 2.9+7.1=10
4. 6 1/3 + 3 2/3 =10
5. 4 3/5 + 5 2/5=10
6. 9.01+.99=10
7. 3.72+6.28 = 10
8. 8 8/9+ 1 1/9=10
IQR = 40
1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.
We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.
40, 45, 50, 60, 60, 75, 90, 90, 120
Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;
IQR = 90 - 50 = 40
Answer:
7√2 or approx. 9.89949
Step-by-step explanation:
distance between two points is
d=√(∆x^2+∆y^2)
where...
d is distance
∆x is change in x value
and ∆y is change in y value
In this problem ∆x=(-3)-4=(-7)
∆y=5-(-2)=7
plugging in those values gives us
d=√((-7)^2+7^2)
Solving this expression gives us
d=√(49+49)=√98
After simplifying the radical we are left with 7√2 or about 9.89949.
Answer:
Well on my end i got 47.12, with pi included
Step-by-step explanation:
