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NNADVOKAT [17]
2 years ago
11

I need help please 35 points

Mathematics
1 answer:
OLEGan [10]2 years ago
6 0

Answer:

I got 35.2

Step-by-step explanation:

I tried doing it and asked multiple friends on discord. And i did a little research

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There are three squares inside the triangle . Find the area of the third triangle with steps , please
pogonyaev

Answer: 49 cm^2

Step-by-step explanation:

The length of the small pink square box will be:

L^2 = 9

L = sqrt( 9 )

L = 3

The length of the big pink square box will be:

L^2 = 16

L = sqrt( 16 )

L = 4

The length of the yellow square box will be:

4 + 3 = 7

The area of the third square box will be

A = 7^2

A = 49 cm^2

6 0
3 years ago
sarà needs three forth cup of dish soap to make homemade bubble solution. her measuring cup is divided into eighths.what fractio
Lesechka [4]
She will need 6/8 because 3/4 the cup is divided into 8 so we need the denominator to be 8. we multiply 4 x 2 and what every we do to the top happens to the bottom so we also multiply 3 x 2. then we see that sara needs 6/8 cups of dish soap to make her bubbles
6 0
3 years ago
Read 2 more answers
25x+15y=750<br><br> please find the x and y intercept !!
Brums [2.3K]
X(30;0)
y(0;50)
substitue 0 for y and solve for x
substitute 0 in for x and solve for y
4 0
3 years ago
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Please, help I don’t understand what im supposed to do.
Blizzard [7]

Answer:

16,800 votes.

Step-by-step explanation:

In the singing competition 42,000 votes were counted.

The winner received 3/5 of the votes.

The part of the votes that the winner did not receive was 1 - 3/5 = 2/5

So the winner did not receive 2/5 of 42,000 votes which is equivalent to:

\frac{2(42,000)}{5} = 16,800 votes.


3 0
3 years ago
Vertex form is f(x)=a(x-p)^2 +q. How do i determine a?
slamgirl [31]
Y1 is the simplest parabola.  Its vertex is at (0,0) and it passes thru (2,4).  This is enough info to conclude that y1 = x^2.

y4, the lower red graph, is a bit more of a challenge.  We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).

Let's try this:  assume that the general equation for a parabola is 
y-k = a(x-h)^2, where (h,k) is the vertex.  Subst. the known values,

-3-(-4) = a(2-0)^2.  Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.

The equation of parabola y4 is   y+4 = (1/4)x^2

Or you could elim. the fraction and write the eqn as 4y+16=x^2, or

4y = x^2-16, or    y = (1/4)x - 4.  Take your pick!  Hope this helps you find "a" for the other parabolas.


8 0
3 years ago
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