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kirza4 [7]
3 years ago
10

-1/2x-3=4 what is X​

Mathematics
2 answers:
kifflom [539]3 years ago
5 0

Answer:

x = -14

Step-by-step explanation:

-1/2x - 3 = 4

-1/2 * x = 4+3

-1/2 * x = 7

x = 7/(-1/2)

x = -14

Good luck with your schoolwork/homework!

---------------------------------------------------------------------

Apologies in advance for wrong answers or bad explanation.

slava [35]3 years ago
3 0

Answer:

x=-14

Step-by-step explanation:

First rewrite your equation in a simpler form.

-\frac{1}{2}x-3=4

Add 3 to both sides of the equation

-\frac{1}{2}=7

Multiply both sides by -\frac{1}{2}.

x=-14

Hope this helps! Wouldn't mind a brainliest either :).

-MoCKEry

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9 whole 2/3 + 4 whole 7/9=
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<u>Answer</u>

14 4/9

<u>Turn 9 2/3 into an Improper Fraction</u>

Multiply 9*3 and get 27. Now add 2 and get 29 (Denominator stays the same)

9 2/3 = 29/3

<u>Turn 4 7/9 into an Improper Fraction</u>

Multiply 4*9 and get 36. Now add 7 and get 43 (Denominator stays the same)

4 7/9 = 43/9

<u>Add</u>

29/3 + 43/9 = 130/9

<u>Turn 130/9 into a Mixed Number (Divide)</u>

130/9 = 14 4/9

Hope This Helps!

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Solve the following system of equations. Write each of your answers as a fraction reduced to lowest terms. In other words, write
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Answer:

x = 57/28

y = -95/84

z = 97/168

Step-by-step explanation:

Use the application in the next link: https://www.zweigmedia.com/RealWorld/tutorialsf1/scriptpivotold.html

Start with the expanded array:

\left[\begin{array}{cccc}1&5&8&1\\3&2&2&5\\-2&-7&2&5\\\end{array}\right]

then using the tool provided, make row operations until you find the solution:

r2 = r2-3r1

\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\-2&-7&2&5\\\end{array}\right]

r3 = r3+2r1

\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\0&3&18&7\\\end{array}\right]

r2 = r2*(-1/13)

\left[\begin{array}{cccc}1&5&8&1\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]

r1 = r1- r2*5

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]

r3 = r3+ r2*-3

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&168/13&97/13\\\end{array}\right]

r3 = r3*13/168

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&1&97/168\\\end{array}\right]

r2 = r2- r3*22/13

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]

r2 = r2+ r3*6/13

\left[\begin{array}{cccc}1&0&0&57/28\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]

Here you have a reduced array an therefore the answers to each variable are on each row:

\left[\begin{array}{c}x\\y\\z\end{array}\right]

8 0
3 years ago
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