Which transformations can be used to map a triangle with vertices A(2, 2), B(4, 1), C(4, 5) to A’(–2, –2), B’(–1, –4), C’(–5, –4
lina2011 [118]
Answer: Hewo, there! your answer is Below
a 90 clockwise rotation about the origin and a reflection over the y-axis
Step-by-step explanation:
Hope this helps you !!!
Have a great day!!!
The system of equations of two unknowns is formulated and solved.




The fraction that satisfies the request is
, since in
the negative signs are canceled and the first fraction is obtained.
144=(x+7)^2 take the square root of both sides...
12=x+7 subtract 7 from both sides...
x=5
So the original was a 5m square.
...
255=WL and you are told that W=L+2 so the equation becomes:
255=(L+2)L
255=L^2+2L
L^2+2L-255=0
L^2+17L-15L-255=0
L(L+17)-15(L+17)=0
(L-15)(L+17)=0 Since L>0...
L=15yd, and since W=L+2, W=17yd so
length=15, width=17yd
50.24
4 squared is 16
16•3.14= 50.24
A= 3.14(4)^2
:)
Answer:
-2x+10
Step-by-step explanation: