The answer is probably the third one or last
Answer:
they are different because of the mode sign on the second 's',
which if you are wondering what it stands for,
it represents only the magnitude of the value needed, not its sign,
let the assumed value of s be -5,
for example iin the first case, s < 3
hence s = -5, and it is true for s < 3
OR
if we take the second case, lsl < 3
that would be s = 5 [ not -5], which would not be true for lsl < 3
i hope u understood it,
if any more questions...please ask :)
|AC| = 2|DE|
⇒
4x - 2 = 2(x + 6) = 2x + 12
2x = 14
x = 7
⇒
|AC| = 26
<span>Let us start with the schnauzers, the easiest one to imagine. Let us assume that there were x number of schnauzers.
Scottie's are 3 more than schnauzers. So their number is x+3
Wire haired terriers are 5 less than twice the number of schnauzers.
So their number is 2x -5 (2x for twice the number of schnauzers)
Now add all these numbers.
That is x + x+3 + 2x-5 = 4x -2
The total number of dogs, 78, is given in the question
Now we know that 4x -2 =78
4x = 78 +2
= 80
Therefore x = 80/4
= 20.
So there were 20 schnauzers, 23 Scottie’s and 35 wire haired terriers</span>
