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bogdanovich [222]
3 years ago
6

What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?

Mathematics
1 answer:
anyanavicka [17]3 years ago
3 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f( - 4) = 4( - 4) + 9 =  - 7

_________________________________

f( - 2) = 4( - 2) + 9 = 1

_________________________________

f(0) = 4(0) + 9 = 9

_________________________________

f(2) = 4(2) + 9 = 17

_________________________________

Thus ;

R = { - 7 , 1 , 9 , 17 }

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The correct answer is (( D )) .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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4 < 4(6y - 12) - 2y       |use distributive property

4 < (4)(6y) + (4)(-12) - 2y

4 < 24y - 48 - 2y       |add 48 to both sides

52 < 26y      |divide both sides by 26

2 < y → y > 2

---------------------------------------------------------

4x + 3 < 3x + 6      |subtract 3 from both sides

4x < 3x + 3       |subtract 3x from both sides

x < 3

------------------------------------------------------------

-5r + 6 ≤ -5(r + 2)        |use distributive property

-5r + 6 ≤ (-5)(r) + (-5)(2)

-5r + 6 ≤ -5r - 10         |add 5r to both sides

6 ≤ -10     FALSE

No solution

-------------------------------------------------------------

-2(6 + s) ≥ -15 - 2s        |use distributive property

(-2)(6) + (-2)(s) ≥ -15 - 2s

-12 - 2s ≥ -15 - 2s        |add 2s to both sides

-12 ≥ -15     TRUE

All real numbers

-------------------------------------------------------------

3s + 6 ≤ -5(s + 2)        |use distributive property

3s + 6 ≤ (-5)(s) + (-5)(2)

3s + 6 ≤ -5s - 10         |subtract 6 from both sides

3s ≤ -5s - 16        |add 5s to both sides

8s ≤ -16         |divide both sides by 8

s ≤ -2

--------------------------------------------------------------

4/3 s - 3 ?

4 0
3 years ago
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