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likoan [24]
4 years ago
5

A mixture of compounds containing diethylamine, phenol, ammonia, and acetic acid is separated using liquid-liquid extraction as

follows: Step 1: Concentrated HCl is added followed by draining the aqueous layer. Step 2: Dilute NaOH is added to the organic layer followed by draining the aqueous layer. Step 3: Concentrated NaOH is added to the organic layer followed by draining the aqueous layer. Which compound would you expect to be extracted into the aqueous layer after the addition of dilute HCl, step 1? Group of answer choices

Chemistry
1 answer:
Luden [163]4 years ago
7 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  ammonia

Explanation:

The mixture contains two base compound which are

           ammonia,

and     diethylamine

Now the addition of HCl which is  a strong acid in step 1  will cause the protonation of  the  two base compound , which makes the soluble hence resulting in them being extracted to the aqueous layer as represented in below

       NH_3  + HCl\to  NH_4 ^{+} + Cl^-

and

     (CH 3CH 2) 2NH + HCl  \to (CH 3CH 2) 2NH_2^{+} + Cl

       

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At 297 K , to what pressure can the carbon dioxide in the cartridge inflate a 3.79 L mountain bike tire? (Note that the gauge pr
Furkat [3]

Answer:

23.226 psi

Explanation:

From the source,

The mass of the carbon dioxide is:- 16.0 g

Molar mass of carbon dioxide = 44.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{16.0\ g}{44.01\ g/mol}

Moles of CO_2 = 0.3636 moles

Volume = 3.79 L

n = 0.3636 mol

Temperature = 297 K

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

P × 3.79 L = 0.3636 mol × 0.0821 L.atm/K.mol × 297 K

⇒P = 2.34 atm

Also,  1 atm = 14.7 psi

So, Pressure = 2.34\times 14.7 psi = 37.926 psi

THus, pressure by the gas is:-

P = Total pressure - Atmospheric pressure = 37.926 - 14.7 psi = 23.226 psi

<u>The carbon dioxide in the cartridge inflate a 3.79 L mountain bike tire to 23.226 psi pressure.</u>

4 0
4 years ago
A container holds 500. mL of CO2 at 20.° C and 735 torr. What will be the volume of the CO2 if the pressure is increased to 807
Alinara [238K]

Answer:- 0.456 L

Solution:- Looking at the given information, only volume and pressure are changing and the temperature is constant. We know that, at constant temperature, the volume of the gas is inversely proportional to the pressure.

P_1V_1=P_2V_2

P_1 = 735 torr

P_2 = 807 torr

V_1 = 500. mL

V_2 = ?

Let's plug in the values in the equation and solve it for final volume.

735torr(500.mL)=807torr(V_2)

V_2=\frac{735torr(500.mL)}{807torr}

V_2=456mL

since, 1 L = 1000 mL

456mL(\frac{1L}{1000mL})

= 0.456 L

So, the volume of carbon dioxide at the new pressure will be 456 mL or 0.456 L.

5 0
3 years ago
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