If the volume of an ideal gas is 22.5 L when it is at a temperature of 365 K, what will the volume be when the gas cools to 338K
1 answer:
Answer:
20.8L = Final volume of the gas
Explanation:
Based on Charles's law, the volume of a gas is directly proportional to the temperature of the gas under pressure constant. The equation is:
<em>where V is volume and T absolute temperature of 1, initial state and 2, final state.</em>
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If initial volume is 22.5L, initial T = 365K and final temperature 338K:
22.5L / 365K = V₂ / 338K
<h3>20.8L = Final volume of the gas</h3>You might be interested in
Answer:
The molar mass of the gas is 36.25 g/mol.
Explanation:
- To solve this problem, we can use the mathematical relation:
ν =
Where, ν is the speed of light in a gas <em>(ν = 449 m/s)</em>,
R is the universal gas constant <em>(R = 8.314 J/mol.K)</em>,
T is the temperature of the gas in Kelvin <em>(T = 20 °C + 273 = 293 K)</em>,
M is the molar mass of the gas in <em>(Kg/mol)</em>.
ν =
(449 m/s) = √ (3(8.314 J/mol.K) (293 K) / M,
<em>by squaring the two sides:</em>
(449 m/s)² = (3 (8.314 J/mol.K) (293 K)) / M,
∴ M = (3 (8.314 J/mol.K) (293 K) / (449 m/s)² = 7308.006 / 201601 = 0.03625 Kg/mol.
<em>∴ The molar mass of the gas is 36.25 g/mol.</em>