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Zanzabum
3 years ago
9

If the volume of an ideal gas is 22.5 L when it is at a temperature of 365 K, what will the volume be when the gas cools to 338K

? Be sure to show your work and proper units.
Chemistry
1 answer:
julsineya [31]3 years ago
6 0

Answer:

20.8L = Final volume of the gas

Explanation:

Based on Charles's law, the volume of a gas is directly proportional to the temperature of the gas under pressure constant. The equation is:

\frac{V_1}{T_1} =\frac{V_2}{T_2}

<em>where V is volume and T absolute temperature of 1, initial state and 2, final state.</em>

<em />

If initial volume is 22.5L, initial T = 365K and final temperature 338K:

22.5L / 365K = V₂ / 338K

<h3>20.8L = Final volume of the gas</h3>
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A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157g of the compound produced 0.213g of CO2 and
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Answer:

C_{7} H_{5}N_{3}O_{6}

Explanation:

First reaction gives you the number of moles or the mass from Carbon and hydrogen

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finally you divide all moles obtained between the smaller number of mole (this is mol of H)

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and you can multiply by  5   to obtain: C_{7} H_{5}N_{3}O_{6}

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