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Zanzabum
3 years ago
9

If the volume of an ideal gas is 22.5 L when it is at a temperature of 365 K, what will the volume be when the gas cools to 338K

? Be sure to show your work and proper units.
Chemistry
1 answer:
julsineya [31]3 years ago
6 0

Answer:

20.8L = Final volume of the gas

Explanation:

Based on Charles's law, the volume of a gas is directly proportional to the temperature of the gas under pressure constant. The equation is:

\frac{V_1}{T_1} =\frac{V_2}{T_2}

<em>where V is volume and T absolute temperature of 1, initial state and 2, final state.</em>

<em />

If initial volume is 22.5L, initial T = 365K and final temperature 338K:

22.5L / 365K = V₂ / 338K

<h3>20.8L = Final volume of the gas</h3>
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When energy is transformed, some is wasted. What is a common form of wasted energy in some energy transformations? (Think about
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Eletrical

Explanation:

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Consider the equilibrium reaction. 2 A + B − ⇀ ↽ − 4 C After multiplying the reaction by a factor of 2, what is the new equilibr
vredina [299]

Answer : The correct expression for equilibrium constant will be:

K_c=\frac{[C]^8}{[A]^4[B]^2}

Explanation :

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The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

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The given equilibrium reaction is,

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3 years ago
Hello can you please help me to solve above fill in the blank questions ​
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3 years ago
Given the reaction: 4A1 + 302 - 2A1,O, How many grams of Al will be
dlinn [17]

Answer:

The answer to your question is 27 g of Al

Explanation:

Data

mass of Al = ?

moles of Al₂O₃ = 0.5

The correct formula for the product is Al₂O₃

Balanced chemical reaction

               4Al + 3O₂   ⇒   2Al₂O₃

Process

1.- Calculate the molar mass of the product

Al₂O₃ = (27 x 2) + (16 x 3)

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2.- Convert the moles of Al₂O₃ to grams

               102 g ---------------- 1 mol

                 x       ----------------  0.5 moles

                 x = (0.5 x 102) / 1

                 x = 51 g of Al₂O₃

3.- Use proportions to calculate the mass of Al

                4(27) g of Al --------------- 2(102) g of Al₂O₃

                     x               --------------- 51 g

                        x = (51 x 4(27)) / 2(102)

                        x = 5508 / 204

                        x = 27 g of Al

4 0
3 years ago
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