If the volume of an ideal gas is 22.5 L when it is at a temperature of 365 K, what will the volume be when the gas cools to 338K
1 answer:
Answer:
20.8L = Final volume of the gas
Explanation:
Based on Charles's law, the volume of a gas is directly proportional to the temperature of the gas under pressure constant. The equation is:
<em>where V is volume and T absolute temperature of 1, initial state and 2, final state.</em>
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If initial volume is 22.5L, initial T = 365K and final temperature 338K:
22.5L / 365K = V₂ / 338K
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Explanation:
It is known that for a body centered cubic unit cell there are 2 atoms per unit cell.
This means that volume occupied by 2 atoms is equal to volume of the unit cell.
So, according to the volume density
2 atoms =
=
Formula for volume of a cube is . Therefore,
Volume of the cube =
As lattice constant (a) =
=
Therefore, the value of lattice constant is .
And, for bcc unit cell the value of radius is as follows.
r =
Hence, effective radius of the atom is calculated as follows.
r =
=
=
Hence, the value of effective radius of the atom is .