If the volume of an ideal gas is 22.5 L when it is at a temperature of 365 K, what will the volume be when the gas cools to 338K

Question

3 years ago

9

? Be sure to show your work and proper units.

1 answer:

julsineya [31] · Answer 1 · 2022-03-23T11:28:44+03:00

Answer:

20.8L = Final volume of the gas

Explanation:

Based on Charles's law, the volume of a gas is directly proportional to the temperature of the gas under pressure constant. The equation is:

$\frac{V_1}{T_1} =\frac{V_2}{T_2}$

<em>where V is volume and T absolute temperature of 1, initial state and 2, final state.</em>

<em />

If initial volume is 22.5L, initial T = 365K and final temperature 338K:

22.5L / 365K = V₂ / 338K

<h3>20.8L = Final volume of the gas</h3>