Answer:
54.1°C
Explanation:
Now we have the following parameters from the question;
Heat applied (H)= 18.0×10^3 Joules
Mass of the water(m)= 250g= 0.25Kg
Initial temperature of the water (θ1)= 37°C
Final temperature of the water (θ2)= the unknown
Heat capacity of water (c) = 4200JKg-1
From ;
H= mc(θ2-θ1)
Substituting values appropriately
18×10^3= 0.25 × 4200(θ2-37)
18×10^3 = 0.25 × (4200θ2 - 155400)
18×10^3 = 1050θ2 - 38850
18×10^3 + 38850 = 1050θ2
56850 = 1050θ2
θ2= 56850/1050
θ2= 54.1°C
Answer:
Chromium, calcium, and osmium
Explanation:
These elements are metals, considering this, these elements electron shells(orbitals) are further away from the nucleus, with this, their attractions are not as strong as non-metals, so some of their electrons are able to move freely.
When you accumulate many atoms, these metals can form a "sea of electrons" because they all have loose electrons interacting with each other. This allows easy conduction of heat and electricity.
I think i think i think i think i think it’s c
Answer:
Ba
Explanation:
Magnesium is the element of second group and third period. The electronic configuration of magnesium is - 2, 8, 2 or 
There are 2 valence electrons of magnesium.
Fluorine is the element of seventeenth group and second period. The electronic configuration of fluorine is - 2, 7 or 
There is 1 valence electron of fluorine.
They will combine and form 
<u>The same type of compound is formed by the other members of the group 2 since they will have 2 valence electron.</u>
Group 2 includes:- beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra).
Hence, correct options is:- Ba
