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prisoha [69]
3 years ago
8

A computer disk that once sold for $2.25 now sells for 25% less. How much does the computer.

Mathematics
1 answer:
tatuchka [14]3 years ago
7 0

Answer:

$ 1.6875 or $1.69 or $1.70

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Find the volume of th] cylinder. Round your answer to the nearest tenth if necessary. Use 3.14 for 1.
spayn [35]

Answer:197.8

The formula for a cylinder is 3.14*r^2*h but if you don't round to the nearest tenth the the answer is 197.82034.

Step-by-step explanation:Step one mutiply 3^2=9, Step two mutiply 3.14*

9=28.26, Step three mutiply 28.26*7=197.82.But if you round 197.82034 to the nearest tenth which is moving one decimal place to the right you'll will get 197.8.

6 0
3 years ago
in 3 months Us energy giant Enron went from a company with assets of 62bn to a company with depts of 18bn What is the difference
Kaylis [27]
Its just 62-18 so it would be 44bn
7 0
3 years ago
What is 321×23 <br><br> one more thing<br><br> what is 3,829÷1221
Archy [21]
321 times 23 is 7,383
3,829 divided by 1,221 is (rounded to the nearest hundredth) 3.14
(the real number was: 3.13595414)
3 0
3 years ago
Adam went to Target and bought items for $45.05, $9.29, and $0.89. How much did these three
andriy [413]
The answer is 55. 23 dollars because if you add 45.05
+. 9.29
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54.34
+. 0. 89
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55.23
5 0
3 years ago
3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?
Scorpion4ik [409]

Answer:

For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

If \bigtriangleup = 0, the equation has only one solution.

In this problem, we have that:

3x^{2} + kx + 3 = 0

So

a = 3, b = k, c = 3

\bigtriangleup = b^{2} - 4ac

\bigtriangleup = k^{2} - 4*3*3

\bigtriangleup = k^{2} - 36

We will only have one solution if \bigtriangleup = 0. So

\bigtriangleup = 0

k^{2} - 36 = 0

k^{2} = 36

k = \pm \sqrt{36}

k = \pm 6

For k = 6 or k = -6, the equation will have exactly one solution.

3 0
2 years ago
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