Answer:
x= 56
Step-by-step explanation:
86+94= 180 which if supplementary angles have to equal 180°
I don't know if you can tell but what's in red means distribute
then I added 26 on both sides with like terms
on the left side 86+26=112 and right side is left with 2x
then divide both sides by 2 to leave x by itself
112/2= 56 and 2x/2=x
so 56=x
Includes critical information you need to identify the chemical
, Includes warnings about the chemical
, Legible are the requirements for chemical labels
<u>Step-by-step explanation:</u>
Labels need to produce guidance on how to manage the chemical so that chemical users are notified about how to guard themselves. That data about chemical hazards be dispatched on labels using quick visual notations (Legible) to inform the user, granting instant identification of the hazards.
Labels, as described in the HCS, are a relevant group of written, printed or graphic information elements concerning a hazardous chemical that are attached to, printed on, or added to the immediate container of a hazardous chemical, or to the outside packaging.
Answer: it will trave 56.89 meters before coming to rest.
Step-by-step explanation:
This is a geometric progression since the distance travelled (height) by the ball is reducing by a constant ratio, r. Since the number of times that the ball will bounce is infinite, then we would apply the formula for determining the sum of the terms in a geometric progression to infinity which is expressed as
S = a/(1 - r)
where
S = sum of the distance travelled by the ball
a = initial distance or height of the ball
r = common ratio
From the information given,
a = 128/9
r = (32/3)/(128/9) = 0.75
Therefore,
S = (128/9)/(1 - 0.75) = 56.89 meters
Answer:
yp = -x/8
Step-by-step explanation:
Given the differential equation: y′′−8y′=7x+1,
The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)
First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;
y′′−8y′=0
The auxiliary equation will give us;
m²-8m = 0
m(m-8) = 0
m = 0 and m-8 = 0
m1 = 0 and m2 = 8
Since the value of the roots are real and different, the complementary solution (yc) will give us
yc = Ae^m1x + Be^m2x
yc = Ae^0+Be^8x
yc = A+Be^8x
To get yp we will differentiate yc twice and substitute the answers into the original DE
yp = Ax+B (using the method of undetermined coefficients
y'p = A
y"p = 0
Substituting the differentials into the general DE to get the constants we have;
0-8A = 7x+1
Comparing coefficients
-8A = 1
A = -1/8
B = 0
yp = -1/8x+0
yp = -x/8 (particular integral)
y = yc+yp
y = A+Be^8x-x/8
Let the length be l, width w and height h, then
Volume = length x width x height
l = 10cm, w + h = 18cm
V(h) = 10(18 - h)h = 180h - h^2
V(h) = 180h - h^2
