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pashok25 [27]
3 years ago
14

F(n)=93+4(n-1) Complete the recursive formula of f(n)

Mathematics
1 answer:
poizon [28]3 years ago
3 0

Answer:

f(1) = 93

f(n) = f(n - 1) + 4

Step-by-step explanation:

The recursive formula for an arithmetic sequence is given as:

f(1) = a

f(n) = f(n - 1) + d

where a = first term and d = common difference

An arithmetic sequence is in the form:

f(n) = a + d(n - 1)

where a = first term and d = common difference

The common difference in f(n) = 93 + 4(n-1) is 4.

The first term is 93.

The recursive formula is therefore:

f(1) = 93

f(n) = f(n - 1) + 4

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5 0
3 years ago
A total of 30 percent of the geese included in a certain migration study were male. If some of the geese migrated during the stu
Serggg [28]
<h2>Answer:</h2>

<em><u>(B). </u></em>\frac{7}{12}

<h2>Step-by-step explanation:</h2>

In the question,

Let the total number of geese be = 100x

Number of Male geese = 30% = 30x

Number of Female Geese = 70x

Let us say 'kx' geese migrated from these geese.

Number of migrated Male geese = 20% of kx = kx/5

Number of migrated Female geese = 4kx/5

So,

<u>Migration rate of Male geese</u> is given by,

\frac{(\frac{kx}{5})}{30x}

<u>Migration rate of Female geese</u> is given by,

\frac{(\frac{4kx}{5})}{70x}

So,

The ratio of Migration rate of Male geese to that of Female geese is given by,

\frac{\left[\frac{(\frac{kx}{5})}{30x}\right]}{\left[\frac{(\frac{4kx}{5})}{70x}\right]}=\frac{350}{4\times 150}=\frac{7}{12}

Therefore, the<em><u> ratio of the rate of migration of Male geese to that of Female geese is,</u></em>

\frac{7}{12}

<em><u>Hence, the correct option is (B).</u></em>

<em><u></u></em>

6 0
3 years ago
What is the median of this set of data? 1, 2, 5, 6, 9 1 5 8 9
gavmur [86]

Answer:

5.5

Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
F(x) =x^2+6x and g(x)=7-x find (f-g)(x) and (f-g)(9)
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(f-g)(x) = x²+6x - (7-x)
(f-g)(x) = x² + 6x - 7 + x
(f-g)(x) = x² + 7x - 7

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(f-g)(9) = 137
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3 years ago
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