Solve the equation x^(2)-x=5x-25 over the complex numbers. Simplify the answer. Show your work.
1 answer:
Answer: x = 3 + 4i and x = 3 - 4i
where i = sqrt(-1)
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Work Shown:
First get everything to one side
x^2-x = 5x-25
x^2-x-5x+25 = 0
x^2-6x+25 = 0
Now use the quadratic formula. We'll plug in a = 1, b = -6, c = 25
![x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-6)\pm\sqrt{(-6)^2-4(1)(25)}}{2(1)}\\\\x = \frac{6\pm\sqrt{-64}}{2}\\\\x = \frac{6\pm8i}{2} \ \ \text{ where } i = \sqrt{-1}\\\\x = \frac{2(3\pm4i)}{2}\\\\x = 3\pm4i\\\\x = 3+4i \ \text{ or } \ x = 3-4i\\\\](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B-%28-6%29%5Cpm%5Csqrt%7B%28-6%29%5E2-4%281%29%2825%29%7D%7D%7B2%281%29%7D%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B6%5Cpm%5Csqrt%7B-64%7D%7D%7B2%7D%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B6%5Cpm8i%7D%7B2%7D%20%5C%20%5C%20%5Ctext%7B%20where%20%7D%20i%20%3D%20%5Csqrt%7B-1%7D%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B2%283%5Cpm4i%29%7D%7B2%7D%5C%5C%5C%5Cx%20%3D%203%5Cpm4i%5C%5C%5C%5Cx%20%3D%203%2B4i%20%5C%20%5Ctext%7B%20or%20%7D%20%5C%20x%20%3D%203-4i%5C%5C%5C%5C)
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