Answer:
432 in^2
Step-by-step explanation:
in similar quadrilaterals, the first point of one quad. corresponds to the first point of the other quad, so in this case UA corresponds with CH.
since CH is 3/4 the length of UA, we can also assume that the other sides in ZUCH are 3/4 the length of their corresponding sides in SQUA.
even though we don't know what quadrilateral SQUA and ZUCH are, we know the area of SQUA is 9/16 times less than ZUCH.
want some proof?
lets say SQUA and ZUCH are rectangle/square
ZUCH: 4X4 = 16
SQUA: 3X3 = 9
now lets say they are trapezoids. We will set ZUCH 2nd base to 8 and height to 16, therefore SQUA bases will be 3 and 6, and the height will be 12 (multiply ZUCH lengths by 3/4)
ZUCH = (b1+b2)(h)/2 = (4+8)(16)/2 = 96
SQUA = (b1+b2)(h)/2 = (3+6)(12)/2 = 54
simplify 96/54 = 16/9
now we can multiply 243 by our factor 16/9 to find the area of SQUA.
243 * 16/9 = 432 in^2
Answer:
132
Step-by-step explanation:
es ciento treinta y dos
Answer:
what is the question
Step-by-step explanation:
Answer: 20 hours
Step-by-step explanation:
Since, One watch is slow and loses two minutes every hour
⇒ 1 hour of slow watch = 62 minutes
And, the other one is fast and gains one minute every hour.
⇒ 1 hour of fast watch = 59 minutes,
Hence, in 1 hour, the difference between slow and fast watch in 1 hour = 62 - 59 = 3 minutes.
⇒ The between slow and fast watch in 20 hours = 20 × 3 = 60 minutes or 1 hour.
Hence, after 20 hours the difference between the watches will be 1 hours.
Answer:
100 students
Step-by-step explanation:
10% of students in 7th grade ----- 10 students
<em>Divide</em><em> </em><em>by</em><em> </em><em>1</em><em>0</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
1% of students in 7th grade ----- 10 ÷10= 1 student
<em>×</em><em>100</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
100% of students in 7th grade ----- 1 ×100= 100 students