✿————✦————✿————✦————✿
The answer is: <u>2(k2−4k)(2c+5)</u>
✿————✦————✿————✦————✿
Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
✿————✦————✿————✦————✿
I could be wrong but I think you solve for y then graph it then find where the lines intersect. You’re using ed puzzle though so just rewatch the part of the video and you’ll get the answer.
<span> we have that
standard form of equation for parabola:
(x-h)^2=-4p(y-k)
(h,k) --------->being the (x,y) coordinates of the vertex.
Parabola opens downwards because focus is below vertex on the axis of symmetry.
For given problem:
</span><span>vertex: (-3,2)
axis of symmetry: x=-3
p=distance from vertex to focus on the axis of symmetry=2-(-1)=3
4p=12
Directrix: y=2+p=5
Equation:
(x+3)^2=-12(y-2)
the answer is </span>(x+3)^2=-12(y-2)
Answer:
(x, y) -> (x+5, y+3)
Step-by-step explanation:
The answer is C. (True) did some research and that’s what all my sources say ;)
